Answer:
total time = 65 seconds
total distance = 1554 meters
Explanation:
kinematic equation:
final velocity = initial velocity + acceleration multiplied by time
v_1 = v_0 + at
28 m/s = 0 m/s + 2 m/s^2 (t)
t = 14 seconds
a) total time = 14 + 46 + 5 = 65 seconds
b) must solve for total distance and divide it by time.
d_1 = v_0t + 1/2 a * t^2
d_1 = 0 + 0.5(2) * 14^2
d_1 = 196 meters
d2 = vt
d2 = 28 *46
d2 = 1288 meters
v_1 = v_o + at
0 = 28 + a(5)
- 28/5 = a
a = - 5.6 m/s^2
d_3 = v_0t + 1/2 a * t^2
d_3 = 28 (5) - 0.5(5.6)*5^2
d_3 = 70 meters
total distance = d1 + d2 + d3 = 196 + 1288 + 70 = 1554 meters
Answer:
For this given plane monochromatic electromagnetic wave with wavelength λ=598 nm, the wavenumber is 
.
Explanation:
For a plane electromagnetic wave we have that the electrical and magnetic field are:
In this case we have the data for the magnetic field. We are told that the magnetic field in a plane electromagnetic wave with wavelength λ=598 nm, propagating in a vacuum in the z direction (
) is described by
(
are the unit vectors in the x,y,z directions respectively)
The wavenumber k is a measure of the spatial frequency of the wave, is defined as the number of radians per unit distance:
where λ is the wavelength
So we get that
The wavenumber is
.
Answer:
<h2>9.3kN</h2>
Explanation:
Step one:
given data
mass of bullet= 0.02kg
speed v=700m/s
time taken =1.5ms= 0.0015 seconds
Step two:
we know that from the first law
F=ma-----1 first law of motion
also, we know that
a=v/t----2
put a=v/t in equation 1 we have
F=mv/t
Step three:
substitute our given data to find force
F=0.02*700/0.0015
F=14/0.0015
F=9333.33N
F=9.3kN
<u>The average force exerted is 9.3kN</u>
Answer:
A) mr = 100 kg
B) Fr = 210N
C) Ft = -199.5N
Explanation:
By conservation of the momentum:
mt*Vo = (mr + mt) * Vf Solving for mr:
mr = mt*Vo / Vf - mt = 100 kg
The average force on the receiver:
mr *(Vf - 0) = Fr * Δt Solving for Fr:
Fr = 210 N
The average force on the tackler:
mt * (Vf - Vo) = Ft * Δt Solving for Ft:
Ft = -199.5 N
