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zysi [14]
3 years ago
12

The largest hailstone every measured fell in Vivian, Nebraska in 2010. The circumference of that hailstone was 19 inches. Using

the circumference and the information below, answer the following questions. le Kinetic Energy 0.5MassVelocity (Units: Mass -> kg, Velocity > m/s) Density of the ice in the hail stones 29 Jbs/ft The volume of a sphere is (4/3) #x x r3 The fall velocity of a hailstone in still air can be approximated using this equation V -kVd where k-20 if d (the diameter of the stone) is given in centimeters. V will have units of meters per second (m/s) as long as d is in cm. Density - Mass/Volume Assume the hailstone was spherical (it was actually oblate and measured 8 inches across) and in cm- and in feet What was the diameter of the hailstone in inches What was the total volume of the hailstone in cubic inches What was the fall velocity of this hailstone in m/s What was the total mass of the hailstone in kg What was the total kinetic energy of this hailstone? and cubic feet and in mph and lbs
Physics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

6.04788 in

115.82654\ in^3

78.38779 m/s

0.88159 kg

34.55294 J

Explanation:

Circumference is given by

c=2\pi r\\\Rightarrow r=\dfrac{c}{2\pi}\\\Rightarrow r=\dfrac{19}{2\pi}\\\Rightarrow r=3.02394\ in

Diameter is given by

d=2r\\\Rightarrow d=2\times 3.02394\\\Rightarrow d=6.04788\ in

The diameter is 6.04788 in

6.04788\times 2.54=15.3616152\ cm

Volume of sphere is given by

v=\dfrac{4}{3}\pi r^3\\\Rightarrow v=\dfrac{4}{3}\pi 3.02394^3\\\Rightarrow v=115.82654\ in^3

The volume is 115.82654\ in^3

115.82654\times \dfrac{1}{1728}=0.06702\ ft^3

Fall velocity is given by

V=k\sqrt{d}\\\Rightarrow V=20\sqrt{15.3616152}\\\Rightarrow V=78.38779\ m/s

The velocity of the fall will be 78.38779 m/s

Mass is given by

m=\rho v\\\Rightarrow m=29\times 0.06702\\\Rightarrow m=1.94358\ lb

1.94358\ lb=1.94358\times \dfrac{1}{2.20462}=0.88159\ kg

The mass is 0.88159 kg

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}0.88159\times 78.38779\\\Rightarrow K=34.55294\ J

The kinetic energy is 34.55294 J

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3 0
3 years ago
A heat engine operating at steady state delivers a power output of 15.5 hp. The engine receives energy by heat transfer in the a
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Answer:

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Explanation:

Given:

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The conversion factor is 1.36 KW per hp.

                                 W_out = 15.5 [hp] * [KW] / 1.36 [hp]

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- Given that there are 50 cycles in 60 sec. We will use direct proportionality to calculate the number of cycles per second:

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                                 x = 50/60 = 0.8333 cycles /s

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                                 w_cycle = 13.68 KJ / cycle

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