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zysi [14]
3 years ago
12

The largest hailstone every measured fell in Vivian, Nebraska in 2010. The circumference of that hailstone was 19 inches. Using

the circumference and the information below, answer the following questions. le Kinetic Energy 0.5MassVelocity (Units: Mass -> kg, Velocity > m/s) Density of the ice in the hail stones 29 Jbs/ft The volume of a sphere is (4/3) #x x r3 The fall velocity of a hailstone in still air can be approximated using this equation V -kVd where k-20 if d (the diameter of the stone) is given in centimeters. V will have units of meters per second (m/s) as long as d is in cm. Density - Mass/Volume Assume the hailstone was spherical (it was actually oblate and measured 8 inches across) and in cm- and in feet What was the diameter of the hailstone in inches What was the total volume of the hailstone in cubic inches What was the fall velocity of this hailstone in m/s What was the total mass of the hailstone in kg What was the total kinetic energy of this hailstone? and cubic feet and in mph and lbs
Physics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

6.04788 in

115.82654\ in^3

78.38779 m/s

0.88159 kg

34.55294 J

Explanation:

Circumference is given by

c=2\pi r\\\Rightarrow r=\dfrac{c}{2\pi}\\\Rightarrow r=\dfrac{19}{2\pi}\\\Rightarrow r=3.02394\ in

Diameter is given by

d=2r\\\Rightarrow d=2\times 3.02394\\\Rightarrow d=6.04788\ in

The diameter is 6.04788 in

6.04788\times 2.54=15.3616152\ cm

Volume of sphere is given by

v=\dfrac{4}{3}\pi r^3\\\Rightarrow v=\dfrac{4}{3}\pi 3.02394^3\\\Rightarrow v=115.82654\ in^3

The volume is 115.82654\ in^3

115.82654\times \dfrac{1}{1728}=0.06702\ ft^3

Fall velocity is given by

V=k\sqrt{d}\\\Rightarrow V=20\sqrt{15.3616152}\\\Rightarrow V=78.38779\ m/s

The velocity of the fall will be 78.38779 m/s

Mass is given by

m=\rho v\\\Rightarrow m=29\times 0.06702\\\Rightarrow m=1.94358\ lb

1.94358\ lb=1.94358\times \dfrac{1}{2.20462}=0.88159\ kg

The mass is 0.88159 kg

Kinetic energy is given by

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}0.88159\times 78.38779\\\Rightarrow K=34.55294\ J

The kinetic energy is 34.55294 J

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two wires have the same length, but the second has twice the diameter of the first. find the resistance of the second wire if th
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2ω is the resistance of the second wire if the resistance of the first is 4ω if two wires have the same length, but the second has twice the diameter of the first.

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R = ρl/A

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R2=2ω

Resistance is the capacity of a conductor to obstruct the passage of an electric current through it. It is controlled by the interaction of the applied voltage and the electric current passing through it.

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28. Identify whether the following objects are in
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Answer:

a. A baseball after it has been  hit - not in free fall

b. A rock that is thrown in the  air - not in free fall

c. The moon - free-fall

d. A paper airplane - not in free fall

e. A bird flying - not in free fall

Explanation:

  1. The free-fall is defined as the falling of an object due to the action of gravity. The object is not experiencing any other force neglecting the air resistance.
  2. If an object is in free-fall, the direction of its motion is directed towards the center of the earth. It does not have a horizontal component of velocity.
  3. If the body is under free-fall, but a centripetal force acts on it where it is equal to the gravitational force at that point. The object will have two components of velocity along the tangential line, perpendicular to the radius of the orbit.

a. A baseball after it has been  hit - not in free fall according to point 1 & 2.

b. A rock that is thrown in the  air - not in free fall according to point 1.

c. The moon - free-fall according to point 3.

d. A paper airplane - not in free fall according to point 1 & 2.

e. A bird flying - not in free fall according to point 1 & 2.

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3 years ago
Where is a proton located within an atom?
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Answer:

in the nucleus of the atom

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a p 3 x

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An electric motor exerts a constant torque of 10 Nm on a grindstone mounted on its shaft. The moment of inertia of the grindston
Dmitry_Shevchenko [17]

Answer:

Angular acceleration = 5 rad /s ^2

Kinetic energy = 0.391 J

Work done = 0.391 J

P =6.25 W

Explanation:

The torque is given as moment of inertia × angular acceleration

angular acceleration = torque/ moment of inertia

= 10/2= 5 rad/ s^2

The kinetic energy is = 1/2 Iw^2

w = angular acceleration/time

=5/8= 0.625 rad /s

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The work done is equal to the kinetic energy of the motor at this time

W= 0.391 J

The average power is = torque × angular speed

= 10× 0.625

P = 6.25 W

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