Answer:
34.51
Explanation:
k=1/2mv² is the kenetic energy equation to fill is in
k=[1/2(0.235)×50]²
Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in N ]
From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)
(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183
= 0.0318 (to three significant figures)
(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm (to three significant figures)
Answer:
Explanation:
Given:
- original frequency of sound wave,
- speed of the sound source,
- original speed of sound wave from the source,
<u>According to the Doppler's effect:</u>
The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.
The velocity of the observer, 
