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steposvetlana [31]
3 years ago
10

Let a be the sum of the last four digits and let b be the last digit of your 8-digit student id. (example: for 20245347, a = 19

and b = 7) on a road trip, a driver achieved an average speed of (48.0+a) km/h for the first 54.0 km and an average speed of (43.0-b) km/h for the remaining 86.0 km. what was her average speed (in km/h) for the entire trip? round your final answer to three significant figures
Mathematics
1 answer:
pav-90 [236]3 years ago
6 0

Using the student id given above, a = 19 and b = 7

Average speed for the first 54 km = 48+a km/h

Plug a = 19

Average speed for the first 54 km = 48+19 = 67 km/h

Average speed for remaining 86 km = 43-b km/h where b = 7

Average speed = 36 km/h

Average speed of entire journey = total distance / total time taken

speed = \frac{distance}{time}  and  time = \frac{distance}{speed}

Time taken to cover 54 km = \frac{54}{67} hr

Time take to cover 86 km = \frac{86}{36} hr

Total time taken = 3.2 hours.

Total distance = 86+54= 140 km

Average speed of the entire trip = \frac{140}{3.2} = 43.75 km/ h

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Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

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c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

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SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

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√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

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