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LenKa [72]
2 years ago
6

The vertical support element inside a wall to which wall finish material is attached is called a

Engineering
1 answer:
posledela2 years ago
6 0

The vertical support element inside a wall to which wall finish material is attached is called a: stud.

<h3>Who is a construction manager?</h3>

A construction manager can be defined as an individual (professional) who has acquired the requisite skills and training to plan, design, develop and construction of a structural project, from start to finish.

This ultimately implies that, a construction manager is saddled with the responsibility of providing and overseeing the use of mineral resources, tools, equipment such as a stud, and raw materials, during the construction of a structural project.

In Engineering, a stud simply refers to the vertical support element that is fitted inside a wall to which wall finish material is attached by a construction manager or other project members.

Read more on stud here: brainly.com/question/11428408

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# 45 You are driving on a two-lane highway and the vehicle behind you wants to pass. You should
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Signal the driver behind you when it is safe to pass by turning on your four-way emergency flashers.

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2 years ago
The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any frictio
Dmitrij [34]

Complete Question

The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass.V = -18 m What is v?X km/h

Answer:

v=23.6m/s

Explanation:

Velocity v_c=18.0km/h

Radius r=21m

initial velocity uu=19=>5.27778

Generally the equation for Angle is mathematically given by

\theta=\frac{v_c}{2r}

\theta=\frac{18}{2*21}

\theta=0.45

\theta=25.7831 \textdegree

Generally

Height of mass

h=\frac{rsin\theta}{\theta}

h=\frac{21sin25.78}{0.45}

h=20.3m

Generally the equation for Work Energy is mathematically given by

0.5mv_0^2+mgh=0.5mv^2

Therefore

v=\sqrt{u^2+2gh}

v=\sqrt{=5.27778^2+2*9.81*20.3}

v=23.6m/s

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3 years ago
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Answer:

b

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