Answer:
The elastic modulus of the steel is 139062.5 N/in^2
Explanation:
Elastic modulus = stress ÷ strain
Load = 89,000 N
Area of square cross section of the steel bar = (0.8 in)^2 = 0.64 in^2
Stress = load/area = 89,000/0.64 = 139.0625 N/in^2
Length of steel bar = 4 in
Extension = 4×10^-3 in
Strain = extension/length = 4×10^-3/4 = 1×10^-3
Elastic modulus = 139.0625 N/in^2 ÷ 1×10^-3 = 139062.5 N/in^2
<em>Logs.</em>
<em>Like data logs. Sometimes people make these logs to keep tabs on other people or to get important information put down somewhere that way it is saved and can be looked back upon later. Anytime someone makes an action on the computer, it makes a TMP file representing a log of what you want it to do before the computer quickly get's rid of the file.</em>
<em>-Ɽ3₮Ɽ0 Ⱬ3Ɽ0</em>
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Answer:
t = 1456.8 sec
Explanation:
given data:
contant k = 2.60*10^{-6}
rate of crystallization is 0.0013 s-1
rate of transformation is given by

use specifies value to solve 
it is ime required for 50% tranformation

Avrami equation is given by






n = 1.88
second degree of recrystalization may be determine by rearranging original avrami equation
![t = [\frac{-ln(1-y)}{k}]^{1/n}](https://tex.z-dn.net/?f=t%20%3D%20%5B%5Cfrac%7B-ln%281-y%29%7D%7Bk%7D%5D%5E%7B1%2Fn%7D)
for 90%completion
![t = [\frac{-ln(1-0.9)}{2.60*10^{-6}}]^{1/1.88}](https://tex.z-dn.net/?f=t%20%3D%20%5B%5Cfrac%7B-ln%281-0.9%29%7D%7B2.60%2A10%5E%7B-6%7D%7D%5D%5E%7B1%2F1.88%7D)
t = 1456.8 sec