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3 years ago

Why should females not be concerned about developing manly muscles? Please help

Engineering

1 answer:

GaryK [48]3 years ago

4 0

Answer:

Women's bodies only produce a fraction of the muscle building hormone testosterone. Therefore they are not able to look too masculere that easily. Female bodybuilders go through specific training and diet for years to look the way they do.

Explanation:

PLEASE MARK BRAINLIEST!!

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What is pre-flush and post flush in petroleum engineering?

cluponka [151]

Answer:

Pre-Flush:

It is also known as In-line Equalization. In this stage of flow equalization, all the flow passes through the equalization basin. It helps in reduction of fluctuation in pollutants concentration and flow rate and helps to control short term surges with the use of basin.

Post-Flush:

Another name for this stage is Off-line Equalization. In this stage, only overflow above a predetermined standard is diverted into the basin. It helps in reducing the fluctuations in loading by a considerable amount and helps to reduce the pumping requirement. It is basically used to capture "first flush" from combined collection systems.

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3 years ago

A thin aluminum sheet is placed between two very large parallel plates that are maintained at uniform temperatures T1 = 900 K, T

Maru [420]

The net radiation heat transfer between the two plates per unit surface area of the plates with shield and without shied are respectively; 2282.76 W/m² and 9766.75 W/m²

<h3>How to find the net radiation heat transfer?</h3>

We are given;

Temperature 1; T₁

Temperature 2; T₂

Temperature 3; T₃

Emissivity 1; ε₁ = 0.3

Emissivity 2; ε₂ = 0.7

Emissivity 3; ε₃ = 0.2

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with shield is;

Q'₁₂ = σ(T₁⁴ - T₂⁴)]/[((1/ε₁) + (1/ε₂) - 1) + ((1/ε₃,₁) + (1/ε₃,₂) - 1)]

Q'₁₂ = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[((1/0.3) + (1/0.7) - 1) + ((1/0.15) + (1/0.15) - 1)]

Q'₁₂,shield = 2282.76 W/m²

The net rate of radiation heat transfer with a thin aluminum shield per unit area of the plates with no shield is;

Q'₁₂,no shield = σ(T₁⁴ - T₂⁴)]/((1/ε₁) + (1/ε₂) - 1))

Q'₁₂,no shield = 5.67 * 10⁻⁸(900⁴ - 300⁴)/[(1/0.3) + (1/0.7) - 1)]

Q'₁₂,no shield = 9766.75 W/m²

Then the ratio of radiation heat transfer for the two cases becomes;

Q'₁₂,shield/Q'₁₂,no shield = 2282.76/9766.75 = 0.2337 or 4/17

Read more about Net Radiation Heat Transfer at; brainly.com/question/14148915

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8 0

2 years ago

Wobble extensions allows the socket to pivot.<br> O True<br> O False

Agata [3.3K]

True

(I’m not sure if that’s right a picture below may help with the answer too)

4 0

3 years ago

We have a credit charge that is trying to process but we do not remember signing up and email login is not working? Is there a w

Dmitry_Shevchenko [17]

Answer:

Explanation:

In such a case, one way to check the <em>credit charge</em> is to <u>contact your bank, </u>doing so would allow the bank to check your account properly to determine where the transaction was originated from.

Another way you could check is to contact the online merchant where such a transaction was initiated.

6 0

3 years ago

Construct a Mohr circle for the stress element at A in problem 2. Using ruler and compass, draw the Mohr circle to the scale. Dr

serious [3.7K]

Answer:

hello your question is incomplete attached below is the missing diagram to the question and the detailed solution

Answer : principal stresses : 0.82 MPa, -33.492 MPa

shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

Explanation:

The principal stress ( б1 ) = 0.82 MPa

( б2 ) = -33.492 MPa

The shear stress = 17.157 MPa

∅ = 9.09 ≈ 10°

attached below is the detailed solution and the Mohr's circle

7 0

3 years ago