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Leno4ka [110]
2 years ago
5

Find an equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4.

Physics
1 answer:
m_a_m_a [10]2 years ago
7 0

An equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4 is x(t)=2t+2,y(t)=t^4.

<h3>What is tangent?</h3>

In calculation, the digression line to a plane bend at a given point is the straight line that "simply contacts" the bend by then. Leibniz characterized it as the line through a couple of boundlessly close focuses on the bend. The chart of digression is intermittent, implying that it rehashes the same thing endlessly. In contrast to sine and cosine in any case, digression has asymptotes isolating every one of its periods. The space of the digression capability is all genuine numbers with the exception of at whatever point cos⁡(θ)=0, where the digression capability is vague. Assuming they stroll in an orderly fashion, they are fundamentally following a digression way for the shape that is made inside the fencing.

Learn more about tangent, refer:

brainly.com/question/12585907

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Plzzz help will give brainlist
zhenek [66]

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

5 0
3 years ago
An elevator is moving down with an acceleration of 3.36 m/s2.
sergeinik [125]

Answer : 413.44N

Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .

  • From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
  • When a elevator accelerates down , the weight recorded is less than the actual weight .

From the Free body diagram ,

\sf\longrightarrow Weight = mg - ma \\

\sf\longrightarrow Weight = m ( g - a ) \\

  • Mass of the man = 64.2 kg

\sf\longrightarrow Weight = 64.2( 9.8 - 3.36) N\\

\sf\longrightarrow Weight = 64.2 * 6.44 N\\

\sf\longrightarrow \underline{\boxed{\bf Weight_{apparent}= 413.44 N }} \\

5 0
2 years ago
An object of mass 20 kg is raised vertically through a distance of 8 m above ground level. If g = 10 m/s2, what is the gravitati
IgorC [24]

2400joules

Explanation:

P.E

m= 20kg h=8m g=10m

P.E= 20×8×10

=2400joules

6 0
2 years ago
How do solutions differ from other mixtures?
zalisa [80]
The answer is D.
I hope this helps.
7 0
3 years ago
Read 2 more answers
If an object has a constant acceleration, it must be changing velocity at the same rate over and over again..TrueFalse
Dimas [21]
If its accel is constant and not changing from its number then the velocity is changing so True
4 0
3 years ago
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