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r-ruslan [8.4K]
3 years ago
8

explain why when water is poured on a dry class slab it spreads uniformly but it forms spherical droplets on a waxed glass slab​

Physics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer and Explanation:

The texture of the slabs affects the type of bonding the water molecules has with each other.

The dry glass slab allows the water to form cohesive bonds with each other, making the water stick to itself and not the slab, which makes it flow uniformly, or regularly.

The Waxed glass slab has a different texture that forms an adhesive-type bonding with water, making the water stick to the slab at certain parts/forming the spherical droplets.

<u><em>#teamtrees #PAW (Plant And Water)</em></u>

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A worker uses a cart to move a load of bricks a distance of 10m across a parking lot. if he pushes the cart with a constant forc
andriy [413]

Answer:

2090 J

Explanation:

the work done to move the cart is equal to the product between the force applied and the distance traveled:

W=Fd

In this case, the force applied is F=209 N, while the distance covered is d=10 m, therefore the work done is

W=Fd=(209 N)(10 m)=2090 J

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D. write down the coefficients
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al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri
3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

F=kx

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

F=2 N

x=4 cm

So the spring constant is

k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm

Later, the force is tripled, so the new force is

F'=3F=3(2)=6 N

Therefore, the new elongation is

x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm

2)

In this second problem, we know that the elongation of the spring now is

x=6 cm

From part a), we know that the spring constant is

k=0.5 N/cm

Therefore, we can use the following equation to find the force:

F=kx

And substituting k and x, we find:

F=(0.5)(6)=3 N

So, the force to produce an elongation of 6 cm must be 3 N.

6 0
3 years ago
A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway
Andru [333]

Answer:

<em>63.44 rad/s</em>

<em></em>

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet v_{1} = 250 m/s

final velocity of bullet v_{2} = 140 m/s

loss of kinetic energy of the bullet = \frac{1}{2}m(v^{2} _{1} - v^{2} _{2})

==> \frac{1}{2}*0.0033*(250^{2}  - 140^{2} ) = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = \frac{1}{2} mv^{2}

70.785 = \frac{1}{2}*0.25*v^{2}

566.28 = v^{2}

v= \sqrt{566.28} = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>

5 0
3 years ago
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