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Readme [11.4K]
2 years ago
12

An elevator is moving down with an acceleration of 3.36 m/s2.

Physics
1 answer:
sergeinik [125]2 years ago
5 0

Answer : 413.44N

Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .

  • From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
  • When a elevator accelerates down , the weight recorded is less than the actual weight .

From the Free body diagram ,

\sf\longrightarrow Weight = mg - ma \\

\sf\longrightarrow Weight = m ( g - a ) \\

  • Mass of the man = 64.2 kg

\sf\longrightarrow Weight = 64.2( 9.8 - 3.36) N\\

\sf\longrightarrow Weight = 64.2 * 6.44 N\\

\sf\longrightarrow \underline{\boxed{\bf Weight_{apparent}= 413.44 N }} \\

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A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

mass of m_2=0.8 kg dropped at r=0.3 m from center

let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

L_1=L_2

\left ( \frac{m_1R^2}{2}\right )\omega =\left ( \frac{m_1R^2}{2}+m_2r^2\right )\omega _2

\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

26.01\times 40=26.082\times \omega _2

\omega _2=39.88 rad/s

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3 years ago
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The layer of Earth that we live on
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Which of the following correctly describes the relative air pressure at the center of a hurricane, with respect to the horizonta
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Explanation:

The pressure of hurricane which is high decreases gradually as we move higher . The pressure is maximum at the surface . Hence the relative air pressure is higher at the surface and low at the top . Like wise the pressure is low at the center and keeps on increasing when we move outside . Hence the answer is pressure is high at surface and low aloft.

6 0
3 years ago
a person complete a 100m race in 11s. He accelerates for the first two second and then maintains the velocity till the end. what
hjlf

The maximum velocity reached by the person is determined as 11.1 m/s.

<h3>Area under velocity - time graph</h3>

The area under the velocity time graph is the total displacement of the person.

Total Area = area of triangle formed during first 2 seconds + area of rectangle during the last 8 seconds

100 = ¹/₂(2v) + v(11 - 2)

where;

  • v is the maximum velocity

100 = v + 8v

100 = 9v

v = 100/9

v = 11. 1 m/s

Thus, the maximum velocity reached by the person is determined as 11.1 m/s.

Learn  more about maximum velocity here: brainly.com/question/20595261

#SPJ1

4 0
1 year ago
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