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vagabundo [1.1K]
3 years ago
5

supose you have two wires of equal length made from same material. how is it possible for the wires to have different resistance

s
Physics
1 answer:
Ivenika [448]3 years ago
6 0
I'm not sure but I had this question on a benchmark I think its the density of the wire  you need to  find the density or the mass I'm not sure but i do remember this question 
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A student weighing 120 lbs climbs a 12 ft flight of stairs in 9 seconds. how much power did the student create?
Alex Ar [27]
Power can be calculate through the equation,
                        Power = Force x velocity

It should be noted that velocity is calculated by dividing displacement by time. Thus, from the given in this item we can calculate for the power. 
                       Power = (120 lb) x (12 ft/9 s)
                         <em> </em><span><em>Power   = 160 lb.ft/s</em></span>
7 0
3 years ago
A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
valina [46]

Answer:

They will meet at a distance of 7.57 m

Given:

Initial velocity of policeman in the x- direction, u_{x} = 10 m/s

The distance between the buildings, d_{x} = 2.0 m

The building is lower by a height, h = 2.5 m

Solution:

Now,

When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.

Thus

From the second eqn of motion, we can write:

h = ut + \frac{1}{2}gt^{2}

h = \frac{1}{2}gt^{2}

2.5 = \frac{1}{2}\times 10\times t^{2}

t = 0.707 s

Now,

When the policeman was chasing across:

d_{x} = u_{x}t + \frac{1}{2}gt^{2}

d_{x} = 10\times 0.707 + \frac{1}{2}\times 10\times 0.5 = 9.57 m

The distance they will meet at:

9.57 - 2.0 = 7.57 m

   

8 0
4 years ago
What is the average velocity of the object?
Andrej [43]

Answer:the rate changes during the position of the object

Explanation:so there is no object that has the same rate but unless it is a specific one like a care but it changes during the position of the object

3 0
3 years ago
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
3 years ago
Question 1 (1 point)
Juli2301 [7.4K]

Hello!

\large\boxed{800Ns}

Remember that impulse is equivalent to:

Impulse = force (N) × time (s)

Plug in the given force and time:

Impulse = 25 × 32

Impulse = 800 Ns

3 0
3 years ago
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