Question

What is the oxidation state of each element in the species Mn(ClO4)3

Answer 1

The oxidation state of the compound Mn (ClO4)3 is to be determined in this problem.

For oxygen, the charge is 2-, the total considering its number of atoms is -24.

Mn has a charge of +3.

TO compute for Mn, we must achieve zero charge overall hence 3 + 3x - 24 = 0 where x is the Cl charge.

Cl charge, x is +7.

Answer 2

First, we'll calculate the valency of chlorine by using the net charge on the ClO₄ ion.
The ClO₄ ion has a charge of -1, while each oxygen atom exhibits a charge of -2. Therefore,

Cl + 4(-2) = -1
Cl = 7

Next, the valency of Mn is calculated by using the overall charge, which is 0

Mn + 3(-1) = 0
Mn = 3

Therefore, the valencies are:
Mn = 3
Cl = 7
O = -2