Question

If the lead can be extracted with 92.5fficiency, what mass of ore is required to make a lead sphere with a 7.00 cm radius? the density of lead is 11.4 g/c

Answer 1

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

To find the mass of ore, the given values are,

The radius of the lead sphere is r = 7.0 cm,

The lead can be extracted with, η = 92.5% = 0.925 efficiency.

What is the Density?

Density is the substance's mass per unit of volume.

We know the density of lead as,

⇒ p = 11.4 g/cm³ .

The volume of the lead sphere is,

V = 4/3πr³

   = 4/3π(7)³

V = 1436.7 cm³.

Mass of the lead present in the lead sphere is,

m = p . V

    = 11.4  × 1436.7

    = 16379 g

m = 16.379 kg

From the expression of efficiency, we calculate the mass of the ore,

η = Mass of lead obtained / Mass of the ore to be taken

0.925 = 16.379 kg / Mass of the ore to be taken

Mass of the ore to be taken = 17.707 kg

If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.

Learn more about Lead extraction,

brainly.com/question/10982537

#SPJ4