If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
To find the mass of ore, the given values are,
The radius of the lead sphere is r = 7.0 cm,
The lead can be extracted with, η = 92.5% = 0.925 efficiency.
<h3>What is the Density?</h3>
Density is the substance's mass per unit of volume.
We know the density of lead as,
⇒ p = 11.4 g/cm³ .
The volume of the lead sphere is,
V = 4/3πr³
= 4/3π(7)³
V = 1436.7 cm³.
Mass of the lead present in the lead sphere is,
m = p . V
= 11.4 × 1436.7
= 16379 g
m = 16.379 kg
From the expression of efficiency, we calculate the mass of the ore,
η = Mass of lead obtained / Mass of the ore to be taken
0.925 = 16.379 kg / Mass of the ore to be taken
Mass of the ore to be taken = 17.707 kg
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
Learn more about Lead extraction,
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