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Anettt [7]
3 years ago
6

HEY CAN ANYONE PLS ANSWER DIS!!!!!!

Physics
2 answers:
Natalija [7]3 years ago
7 0

Answer:

the answer is a

Explanation:

antiseptic1488 [7]3 years ago
3 0

Answer:

I think That All the atoms of a given element are identical in that they have the same number of protons

Explanation:

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In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?
lidiya [134]

Answer: This is the orbit (of the moon around Earth).

An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

5 0
3 years ago
A major feature of the solar system is that as planets get farther away from the sun they, _________ a. Are warmer b. Have fewer
defon
D.
Have a longer revolution time since they definitely do not get warmer, They do not have fewer moons (Jupiter has about 100 and earth has 1) they are not smaller in diameter (Earth v Jupiter)
6 0
2 years ago
What is the angular position in radians of the minute hand of a clock at 2:55?
OleMash [197]
Refer to the diagram shown.

There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.

By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°

Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians  = 2.0944 radians

Answer: (2π)/3 radians ofr 2.0944 radians.

8 0
3 years ago
Read 2 more answers
how would your weight change with time if you were on s space ship traveling away from Earth toward the moon
astra-53 [7]

Well, before we discuss that, I think we have to carefully understand
and agree on something.  We have to be very clear about what we
mean by 'weight' ...  is it what you feel, or is it the product of

           (your mass) x (the acceleration of gravity where you are).

If you're on a space ship, then any time your engine is not burning,
you feel weightless.  It doesn't matter where you are, or what body
you may be near.  If you're not doing a burn, and the only force on
you is the force of gravity, then you don't feel any weight at all.

But of we say that your 'weight' is the product of

           (your mass) times (the acceleration of gravity where you are),

then it depends on where you are, and whether you're close to
the Earth or closer to the moon.  You may not feel it, but you're
going to have weight, and it's going to change during your trip
in space.

You know that the force of gravity depends on how far you are
from the body that's attracting you.

-- As you travel from the Earth to the moon, gravity will pull you
less and less toward Earth, and more and more toward the moon. 

-- Your weight will get less and less, until you reach the point
in space where the gravitational attractions are equal in both
directions.  That's about 24,000 miles before you reach the
moon ... about 90% of the way there.  At that point, your weight
is really zero, because the pull toward the Earth and the pull toward
the moon are equal.

-- From there, the rest of the way to the moon, your weight will
start to grow again.  It begins at zero at the 'magic point', and it
grows and grows until you reach the moon's surface.  When
you're there, your weight has grown to about 1/6 of what you
weigh on Earth, and it won't get any bigger.  If you weigh
120 pounds on Earth, then you weigh about 19.86 pounds on
the moon ... PLUS your space suit, boots, heater/air conditioner,
oxygen tank, radiation shielding, radio, and all the other stuff that
you need to survive on the moon for a few hours.
8 0
3 years ago
Um bloco de prata de massa m= 40g é aquecido de 30°C até 80° C
lesantik [10]

Answer:

a) Q = 111.6 cal

b) T2 = 415.15K = 142°C

Explanation:

a) To calculate the amount oh heat given to the block of silver, you use the following formula:

Q=mc(T_2-T_1)      (1)

m: mass of the block = 40g

T2: final temperature = 80°C = 353.15k

T1: initial temperature = 30°C = 303.25K

c: specific heat of silver = 0.0558cal/g.K

You replace the values of the parameters in the equation (1):

Q=(40g)(0.0558cal/g.K)(353.15K-303.15K)=111.6\ cal

hence, the amount of heat is 111.6 cal

b) The temperature is calculated by solving the equation (1) for T2:

T_2=\frac{Q}{mc}+T_1\\\\T_2=\frac{250cal}{(40g)(0.0558cal/g.K)}+303.15K=415.15K

hence, the final temperature when 250 cal of heat is geiven to the block of silver, is 415.15K

5 0
3 years ago
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