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RSB [31]
2 years ago
5

In addition to reacting with gold (see Problem 21.21), aqua regia is used to bring other precious metals into solution. Balance

the skeleton equation for the reaction with Pt:Pt(s) + NO₃⁻(aq) + Cl⁻(aq) → PtCl₆²⁻(aq) + NO(g)
Chemistry
1 answer:
suter [353]2 years ago
6 0

Aqua regia is used to bring precious metals into the solution .

3Pt(s)+ 4NO^{-} _{3} (aq)+18 Cl^{-} (aq) +16H^{+} =3Pt Cl^{2-} _{6} (aq) +4NO(g) +8 H_{2} O

This is the balanced reaction of Pt (platinum) .

<h3>What is aqua regia ?</h3>

It is a mixture of concentrated nitric acid and hydrochloric acid .there is three part of concentrated HCl and 1 part of concentrated nitric acid .

it is red or yellowish liquid . it is extremely corrosive and can cause skin burns . it is frequently used to dissolve gold and platinum .

The equation of reaction of aqua regia with gold :

Au + 4H^{+} +NO^{-} _{3} +4Cl^{-} =AuCl^{-} _{4} +NO +2H_{2} O

Learn more about aqua regia here :

brainly.com/question/12982022

#SPJ4

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devlian [24]

Answer:

coral reef

Explanation:

6 0
3 years ago
Water is placed in a graduated cylinder and the volume is recorded as 43.5 mL. A homogeneous sample of metal pellets with a mass
Ipatiy [6.2K]

Answer:

1.8g

Explanation:

Initial volume = 43.5ml

Final volume = 49.4ml

Mass = 10.88g

Density = ?

Volume = Final volume - initial volume

= 49.4 - 43.5

= 5.9ml

Density = Mass/volume

Density = 10.88/5.9

= 1.8g/ml

4 0
3 years ago
How many grams of potassium chloride are needed to make 100 ml of a solution containing 250 mosmol/l? (m.w. of potassium is 39 a
LUCKY_DIMON [66]
In dilute solutions, the unit osmolarity is being used. It usually has units milliosmols per liter of solution or mOsmol/L. An osmole defines the number of moles of the solute that would have an effect on the osmotic pressure of the solution. Osmolarity is calculated by the product of the molarity and the number of particles in the solution which is 2 for potassium chloride. We calculate as follows:
Osmolarity = molarity (# of particles)250 mosmol/L ( 1 osmol / 1000 osmol) = x moles / .100 L (2)
x moles = 0.0125 mol KCl
mass KCl = 0.0125 mol KCl ( 39 + 35.5 g/mol) = 0.93125 g KCl
5 0
3 years ago
A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol
ch4aika [34]

If I made no mistake in calculation, the given answer must be correct...(tried my best)



elements   :                        carbon     hydrogen    oxygen       Fluorine

 composition [C]                     24             3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3


(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3


if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula:  [= 100]


Them molecular formula = empirical formula

    
7 0
3 years ago
A 67.2 g sample of a gold and palladium alloy contains 3.17x10^23 atoms. What is the mass percentage of the gold in the alloy?
Karo-lina-s [1.5K]
The answer is A I hope that helps
7 0
3 years ago
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