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2 years ago

What happens when a species is moved from its natural environment?

Chemistry

2 answers:

77julia77 [94]2 years ago

3 0

When a species is moved from its natural habitat it will learn to adapt to the new environment

ziro4ka [17]2 years ago

3 0

Answer:

What may happen is everything where they used to live may change. Like The food cycle or the ecosystem. Here's a example. We took wolves from their natural environment and there was a big impact on what they did. Elks is what they ate all the time and kept their population low enough to where the environment can thrive but when they took the wolves the elks started to eat the berries in which Grizzly Bears need to feast on for their hibernation and they ate shrubs and other plant like stuff to which stuff couldn't grow anymore. The Elk population when from 5000 to 30000 from when they took the wolves that day. Another thing is how beavers build dams to keep water from going to certain places which help humans out too, but all the time the Elks would drink water and leave waste inside the water to where fish and other species inside the water started dying out. So beavers couldn't build. So this is my example of what may happen if a species is moved from their natural ground cause they could also ruin a food chain somewhere else.

Explanation:

Hope this helps

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Explain how a substances flammability can indicate a chemical change.

Marat540 [252]

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May I have brainliest please? :)

4 0

2 years ago

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

IrinaK [193]

Answer:

$49.45~%$

Explanation:

In this case, we have to start with the chemical reaction:

$C_6H_1_2O~->~C_6H_1_0~+~H_2O$

So, if we start with 10 mol of cyclohexanol ( $C_6H_1_2O$ ) we will obtain 10 mol of cyclohexanol ( $C_6H_1_0$ ). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:

$(6*12)+(10*1)=82~g/mol$

With this value we can calculate the grams:

$10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0$

Now, we have as a product 500 mL of $C_6H_1_0$ . If we use the density value (0.811 g/mL). We can calculate the grams of product:

$500~mL\frac{0.811~g}{1~mL}=405.5~g$

Finally, with these values we can calculate the yield:

$%~=~\frac{405.5}{820}x100~=~49.45%$ %= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0

2 years ago

Aluminum is manufactured using electrolysis. Carbon electrodes are used. Describe the nature of the electrolyte.

Aleksandr [31]

Answer:

The traditional electrolyte for aluminium electrolysis is based on molten cryolite (Na3AlF6), acting as solvent for the raw material, alumina (Al2O3).Metals are found in ores combined with other elements. Electrolysis can be used to extract a more reactive metal from the ore.

Aluminum can and is used as both anodes and cathodes in electrochemical cells, but there are some peculiarities to using it as an anode in aqueous solutions. As you note, aluminum forms a passivating oxide layer quite readily, even by exposure to atmosphere. In an aqueous solution, if the potential is high enough, OH− and O2− are generated at the anode, which can then react with the aluminum to produce aluminum oxide. Al^3+ can also be generated directly. The electric field will draw the anions through the growing aluminum oxide layer towards the aluminum surface and the Al^3+ towards the solution, making the oxide layer grow both away from the electrode surface and into the surface of the electrode. In this way, coatings thicker than the normal passivation in air can be produced. However, aluminum oxide is a good electrical insulator, thus if a dense non-porous layer is grown, it will become impossible to pass current through it and growth will stop, leaving a relatively thin oxide layer (this is how the dielectric layers in electrolytic capacitors are made). This is the normal behaviour in aqueous solutions at near-neutral pH (5–7).

However, if a thick aluminum oxide layer is desired (e.g. to produce coatings on aluminum parts for dying or durability), maintaining porosity is necessary to avoid completely blocking access to the surface. One technique that is commonly used is using a low pH solution, which tends to redissolve some of the oxide and neutralize some of the formed OH−, leaving pores in the oxide layer through which the ions can travel and continue to react. These pores also give a good structure to retain dyes or lubricants, but generally need to be sealed after to protect against corrosion.

3 0

2 years ago

In the boxes below, draw three particle diagrams representing the sample

Alexxandr [17]

Answer: 2

Explanation: bencause they are changing

5 0

2 years ago

What statement about gases is true?

kenny6666 [7]

Anything that is true

please write down your question correctly

5 0

2 years ago