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ella [17]
3 years ago
9

A compound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% C, 3.0% H, 16.0% O and 57.0%F. What is the mol

ecular formula of the compound?
Chemistry
1 answer:
ch4aika [34]3 years ago
7 0

If I made no mistake in calculation, the given answer must be correct...(tried my best)



elements   :                        carbon     hydrogen    oxygen       Fluorine

 composition [C]                     24             3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3


(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3


if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula:  [= 100]


Them molecular formula = empirical formula

    
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Lewis structures for the perchlorate ion (ClO4−) can be drawn with all single bonds or with one, two, or three double bonds. Dra
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Answer:

The most important resonance structure is 4 (attached picture). Its bon order is \frac{7}{4} or 1\frac{3}{4}.

Explanation:

A picture with 4 forms of the perchlorate structure is attached. The first structure has simple bonds. The second structure contains a double bond, the third structure has two double bonds and the fourth structure has three double bonds.

Formal charge = group number of the periodic table - number of bonds (number of bonding electrons / 2) - number of non-shared electrons (lone pairs)

The formal charges in the first structure is +3 in chlorine and -1 in oxygen.

The formal charges in the second structure is +2 in chlorine, -1 in oxygen and 0 in the double bond oxygen.

The formal charges in the third structure is +1 in chlorine, -1 in the single bond oxygens and 0 in the double bond oxygens.

The formal charges in the fourth structure is 0 in chlorine, -1 in the single bond oxygen and 0 in the double bond oxygens.

The most important resonance structure is given by:

  • Most atoms have 0 formal charge.
  • Lowest magnitude of formal charges.
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Hence, the fourth structure is the mosr important.

The bond order of the structure is:

Total number of bonds: 7

Total number of bond groups: 4

Bond order= \frac{7}{4} =1\frac{3}{4}

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This bond type is the metallic bond.

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