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Vesna [10]
1 year ago
14

When each of the following pairs of aqueous solutions is mixed, does a precipitation reaction occur? If so, write balanced molec

ular, total ionic, and net ionic equations:
(a) Potassium carbonate + barium hydroxide
Chemistry
1 answer:
Aleks04 [339]1 year ago
6 0

Yes, a precipitation process does take place here. BaCO₃ and KOH are the byproducts of this double displacement reaction, and since BaCO₃ is soluble in solution, it precipitates as a solid.

Molecular: Ba(NO₃)₂(aq) + K₂CO₃(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

The complete ionic reaction can be written as follows:

Ba²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + CO₃²¯(aq) → 2K⁺(aq) + 2NO₃¯(aq) + BaCO₃(s) ⬇︎

All the ions in solution have been written out. Now, on to the net ionic equation:

Ba²⁺(aq) + CO₃²¯(aq) → BaCO₃(s) ⬇︎

<h3>what is precipitation?</h3>

Any liquid or frozen water that condenses in the atmosphere and falls to the ground is known as precipitation. Snow, sleet, and rain are just a few of the variations. One of the three main processes that make up the global water cycle is precipitation, along with evaporation and condensation.

Water vapor in the clouds condenses into increasing-sized droplets of water, forming precipitation. Droplets fall to the Earth when they are sufficiently heavy. The water droplets may freeze to produce ice if a cloud is colder, as it would be at higher elevations. Depending on the temperature within the cloud and at the Earth's surface, these ice crystals eventually discharge to the Earth as snow, hail, or rain.

To learn more about precipitation visit:

brainly.com/question/18109776

#SPJ4

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What name should be used for the ionic compound LiI?

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Sulfuric acid is produced in larger amounts by weight than any other chemical. It is used in manufacturing fertilizers, oil refi
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Answer:

A. -166.6 kJ/mol

B. -127.7 kJ/mol

C. -133.9 kJ/mol

Explanation:

Let's consider the oxidation of sulfur dioxide.

2 SO₂(g) + O₂(g) → 2 SO₃(g)     ΔG° = -141.8 kJ

The Gibbs free energy (ΔG) can be calculated using the following expression:

ΔG = ΔG° + R.T.lnQ

where,

ΔG° is the standard Gibbs free energy

R is the ideal gas constant

T is the absolute temperature (25 + 273.15 = 298.15 K)

Q is the reaction quotient

The molar concentration of each gas ([]) can be calculated from its pressure (P) using the following expression:

[]=\frac{P}{R.T}

<em>Calculate ΔG at 25°C given the following sets of partial pressures.</em>

<em>Part A  130atm SO₂, 130atm O₂, 2.0atm SO₃. Express your answer using four significant figures.</em>

[SO_{2}]=[O_{2}]=\frac{130atm}{(0.08206atm.L/mol.K).298K} =5.32M

[SO_{3}]=\frac{2.0atm}{(0.08206atm.L/mol.K).298K} =0.0818M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0818^{2} }{5.32^{3} } =4.44 \times 10^{-5}

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln (4.44 × 10⁻⁵) = -166.6 kJ/mol

<em>Part B  5.0atm SO₂, 3.0atm O₂, 30atm SO₃  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=\frac{5.0atm}{(0.08206atm.L/mol.K).298K}=0.204M

[O_{2}]=\frac{3.0atm}{(0.08206atm.L/mol.K).298K}=0.123M

[SO_{3}]=\frac{30atm}{(0.08206atm.L/mol.K).298K}=1.23M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{1.23^{2} }{0.204^{2}.0.123 } =296

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 296 = -127.7 kJ/mol

<em>Part C Each reactant and product at a partial pressure of 1.0 atm.  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=[O_{2}]=[SO_{3}]=\frac{1.0atm}{(0.08206atm.L/mol.K).298K}=0.0409M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0409^{2} }{0.0409^{3}} =24.4

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 24.4 = -133.9 kJ/mol

7 0
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What mass of CH3COOH is present in a 250 mL cup of 1.25 mol/L solution of vinegar?
aleksley [76]
If    1000 ml (1 L) of CH₃COOH contain 1.25 mol
let  250 ml  of CH₃COOH contain x

⇒  x =  \frac{250 ml * 1.25mol}{1000 ml}
        
        =  0.3125 mol

∴ moles of CH₃COOH in 250ml is 0.3125 mol

Now, Mass = mole  ×  molar mass
        
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                   = 18.75 g

∴ Mass of CH₃COOH present in a 250 mL cup of 1.25 mol/L solution of vinegar is <span>18.75 g</span>
4 0
3 years ago
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