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OleMash [197]
4 years ago
5

238u undergoes radioactive decay to 234th. how many protons, electrons, and neutrons are gained or lost by the 238u atom during

this process?
Chemistry
1 answer:
user100 [1]4 years ago
4 0
U^235Number of protons = 92 pNumber of electrons = 92 eNumber of neutrons = 235 – 92 = 143n
U^238Number of protons = 92pNumber of electrons = 92eNumber of neutrons = 238 – 92 = 146n
Electron configuration of U atom U = 92 U = [Rn] 5f^6 6d^0 7s^0 U = [Rn] 5f^36d^17s^2, 7s is completely filled and others are less than half filled. 
(_92^238)U  Decays to (_90^234)ThIt loses 2 protons, 2 electrons and loses 2 neutrons Th = [Rn] 6d^2 7s^2 There is no electron in 5f subshell and 6d contains 2e^-, 7s completely filled
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To Find :

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Without wasting much of our time, Here is the correct question.

Hemoglobin molecules in blood bind oxygen and carry it to cells, where it takes part in metabolism. The binding of oxygen hemoglobin(aq) + O2(aq) -------> hemoglobin O2(aq) is first order in hemoglobin and first order in dissolved oxygen, with a rate constant of 4 × 10⁷ L mol⁻¹ s⁻¹. Calculate the initial rate at which oxygen will be bound to hemoglobin if the concentration of hemoglobin is 2 × 10⁻⁹ M and that of oxygen is 5 × 10⁻⁵M.

Answer:

4 × 10⁻⁶ M s⁻¹

Explanation:

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Now, we are also being told to calculate only!, the  initial rate at which oxygen will be bound to hemoglobin.

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rate = k [hemoglobin_{(aq)}][O_{2(aq)}]

Let's not forget that we are so given some parameters;

where

k (rate constant) = 4 × 10⁷ L mol⁻¹ s⁻¹

[ hemoglobin_{(aq) ] = 2 × 10⁻⁹ M

[  O_{2(aq)  ]  =  5 × 10⁻⁵ M

Substituting our data given into the above rate formula, we have:

rate = (4 × 10⁷ L mol⁻¹ s⁻¹) × (2 × 10⁻⁹ M) × (5 × 10⁻⁵ M)

rate = 4 × 10⁻⁶ M s⁻¹     ( given that 1 M = 1 mol L⁻¹ )

∴ the initial rate at which oxygen will be bound to hemoglobin = 4 × 10⁻⁶ M s⁻¹

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