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2 years ago

Compare the relative strength of the two forces B and C. Explain how you determined this comparison by identifying the forces.

Chemistry

1 answer:

Mars2501 [29]2 years ago

4 0

The intermolecular forces or the strength of C is more than that of B.

What are intermolecular forces?

Intermolecular forces are the forces that hold the molecules of any object in a particular state of matter.
It exists between molecules.
These forces are weak when compared with intramolecular forces.
Hydrogen bonding, dipole-dipole, Vander Walls, and ion-dipole are the types of intermolecular forces.
At a short distance, these forces are repulsive but at large distances they are attractive.

Here, we can see that C has dipole-dipole interaction while B has none.

Therefore, it states that the intermolecular forces present in C are much more than that in B.

To learn more about intermolecular forces, visit: brainly.com/question/9007693

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Answer:

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3 years ago

How much 10.0 M HNO must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH

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Explanation:

It is given that molarity of acetic acid = 0.0100 M

Therefore, moles of acetic acid = molarity of acetic acid × volume of buffer

Moles of acetic acid = 0.0100 M × 1.00 L

= 0.0100 mol

Similarly, moles of acetate = molarity of sodium acetat × volume of buffer

= 0.100 mol

When $HNO_{3}$ is added, it will convert acetate to acetic acid.

Hence, new moles acetic acid = (initial moles acetic acid) + (moles $HNO_{3}$ )

= 0.0100 mol + x

New moles of sodium acetate = (initial moles acetate) - (moles $HNO_{3}$ )

= 0.100 mol - x

According to Henderson - Hasselbalch equation,

pH = $pK_{a} + log\frac{[conjugate base]}{[weak acid]}$

pH = $pKa + log\frac{(new moles of sodium acetate)}{(new moles of acetic acid)}$

4.95 = 4.75 + $log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$

$log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = 4.95 - 4.75

= 0.20

$\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = antilog (0.20)

= 1.6

Hence, x = 0.032555 mol

Therefore, moles of $HNO_{3}$ = 0.032555 mol

volume of $HNO_{3}$ = $\frac{moles HNO_{3}}{molarity of HNO_{3}}$

= $\frac{0.032555 mol}{10.0 M}$

= 0.0032555 L

or, = 3.25 (as 1 L = 1000 mL)

Thus, we can conclude that volume of $HNO_{3}$ added is 3.26 mL.

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Drupady [299]

Answer is: The zooplankton can be used to help control algal growth in some coral communities.

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3 years ago

If an isotope of an element has 40 neutrons and a mass number of 79, how many electrons must it have?

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