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dedylja [7]
2 years ago
13

Compare the relative strength of the two forces B and C. Explain how you determined this comparison by identifying the forces.

Chemistry
1 answer:
Mars2501 [29]2 years ago
4 0

The intermolecular forces or the strength of C is more than that of B.

What are intermolecular forces?

  • Intermolecular forces are the forces that hold the molecules of any object in a particular state of matter.
  • It exists between molecules.
  • These forces are weak when compared with intramolecular forces.
  • Hydrogen bonding, dipole-dipole, Vander Walls, and ion-dipole are the types of intermolecular forces.
  • At a short distance, these forces are repulsive but at large distances they are attractive.

Here, we can see that C has dipole-dipole interaction while B has none.

Therefore, it states that the intermolecular forces present in C are much more than that in B.

To learn more about intermolecular forces, visit: brainly.com/question/9007693

#SPJ9

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Which of the following statements concerning coordinate covalent bonds is correct? Group of answer choices One of the atoms invo
lys-0071 [83]
One of the atoms involved must be a metal and the other a nonmetal
6 0
3 years ago
8. A student filled a graduated cylinder with water and read the meniscus at 25.8 mL. The student
fomenos

Answer:

<h2>30.2 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

volume = final volume of water - initial volume of water

From the question

volume = 35.9 ml - 25.8 ml = 10.1 mL

We have

mass = 2.99 × 10.1 = 30.199 g

We have the final answer as

<h3>30.2 g</h3>

Hope this helps you

5 0
3 years ago
What is created by the gravitational pull of the moon?<br> HURRY PLEASE ! I HAVE LIMIT TIME !
seraphim [82]

Answer:

Tides . hope this helps

Explanation:

the tidal force causes earth and its water to bulge out on the side closest to the moon

7 0
3 years ago
________ is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions
Tatiana [17]

Standard enthalpy change of neutralization is the enthalpy change when 1 mole of water is produced by the reaction of an acid and a base under standard conditions.

Enthalpy change of neutralization:

  • Every time enthalpy change of neutralization is calculated, one mole of water is produced.
  • Heat is released when an acid and an alkali react, hence enthalpy changes of neutralization are always negative.
  • The values are always quite comparable for reactions involving strong acids and alkalis, falling between -57 and -58 kJ mol-1.
  • If the reaction is the same in each case of a strong acid and a strong alkali, the enthalpy change is similar.

Learn more about the Enthalpy of neutralization with the help of the given link:

brainly.com/question/15347368

#SPJ4

7 0
2 years ago
Need little help pls
Julli [10]

Answer:

0.354 molal

Explanation:

The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).

Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( 10^{-3} ) and kilo- denotes a factor of one thousand ( {10}^3 ),

1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}.

To calculate the corresponding molality of the solution, the formula

Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)} is used.

Therefore,

Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)

4 0
2 years ago
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