A swimming pool is a solution as it is a solution of chlorinated water
Answer:
the product is Mg(Clo3)2 + AgI
Answer:
The concentration c is equal to Ka
Explanation:
The acid will ionize as observed in the following reaction:
HA = H+ + A-
H+ is the proton of the acid and A- is the conjugate base
. The equation to calculate the Ka is as follows:
Ka = ([H+]*[A -])/[HA]
Initially we have to:
[H+] = 0
[A-] = 0
[HA] = c
During the change we have:
[H+] = +x
[A-] = +x
[HA] = -x
During balance we have:
[H+] = 0 + x
[A-] = 0 + x
[HA] = c - x
Substituting the Ka equation we have:
Ka = ([H+]*[A-])/[HA]
Ka = (x * x)/(c-x)
x^2 + Kax - (c * Ka) = 0
We must find c, having as [H+] = 1/2c. Replacing we have:
(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0
(c^2)/2 + Ka(c / 2 - c) = 0
(c^2)/2 + (-Ka * c/2) = 0
c^2 -(c*Ka) = 0
c-Ka = 0
Ka = c
We know that
Speed of light = wavelength X frequency
Energy of light = h X frequency
Where
h = planck's constant = 6.626 x 10–34 j·s
frequency = speed of light / wavelength = 2.998 x 10^8 m/s / 656.3 X 10^-9
frequency = 4.57 X 10^14 / s
Energy = 6.626 x 10–34 j·s X 4.57 X 10^14 / s = 3.028 X 10^-19 Joules
