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otez555 [7]
3 years ago
7

The three components essential for a fire are:

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
3 0

Hey there


The answer should be : Oxygen, fuel , heat


I hope that's help !

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Which of these humans activities is a serious threat to marine ecosystems
Paraphin [41]

Answer:

Pollution, non native species being introduced, and other human activities

Explanation:

Human activities affect marine ecosystems as a result of pollution, overfishing, the introduction of invasive species,and acidification, which all impact on the marine food web and may lead to largely unknown consequences for the biodiversity and survival of marine life forms.

5 0
3 years ago
Read 2 more answers
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce
Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{3.49}{3.50}=0.997g

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{9.00}{6.00}=1.5g

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0
3 years ago
Concentrated nitric acid is 15.6M and has a density of 1.41g/mL. What is the weight percent of concentrated HNO3?
tankabanditka [31]
Molarity= mol/ liters

since the molarity is given, we can assume that we have 1.0 Liters of solution

15.6 M= mol/ 1 liters---> this means that we have 15.6 moles of HNO3

we need to convert these moles to grams using the molar mass of HNO3

molar mass  HNO3= 1.01 + 14.0 + (3 X 16.0)= 63.01 g/mol

15.6 mol HNO3 (63.01 g/ mol)= 983 grams HNO3

now we have to determine the grams of solution using the assumption of 1 liters of solution and the density

1 liters= 1000 mL

1000 mL (1.41 g/ ml)= 1410 grams solution

mass percent= mass of solute/ mass of solution x 100

mass percent= 63.01/ 1410 x 100= 4.47 %
6 0
4 years ago
A sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02
UNO [17]

I am looking for this answer too. Did you ever find it? I could really use the help

8 0
3 years ago
Read 2 more answers
Please help/show work!
Keith_Richards [23]

Answer:

7.00335g

Explanation:

n=\frac{V}{V_m} \\n = \frac{11.2}{22.4} \\n= 0.5 mol

n=\frac{m}{M} \\m=nM\\m=(0.5)(14.0067)\\m=7.00335g

3 0
2 years ago
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