2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
<em>Step 1</em>. Write the <em>condensed structural formula</em> for 2,3-dimethylbutane.
(CH_3)_2CHCH(CH_3)_2
<em>Step 2</em>. Write the <em>molecular formula</em>.
C_6H_14
<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.
C_6H_14 + O_2 → CO_2 + H_2O
<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).
<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O
<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).
1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O
Oops! <em>Fractional coefficients</em>!
<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..
2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
Maglev trains were created to connect Shanghai Pudong International Airport to Central Pudong. Transrapid, another name for the Maglev train is said to be the fastest train. It can run up to 270/mph in just eight minutes.
Compared to other transportation systems, Transrapid is faster and more cost effective. It has less maintaining coverage and zero sounds compared to the ordinary ones.
This kind of train is one of the most effective means of transportation. It lessens traffic and pollution caused by car emission. It also saves more time for people who are always on the go.
Answer:
2 E16 Hz or 2 * 10^16 Hz
Explanation:
The formula to determine frequency is f = c / λ.
f = frequency
c = speed of light
λ = wavelength
f = 3E8 / 1.5E-8
f = 2E16
This makes sense because UV light exists roughly
between 8E14 Hz and 3E16 Hz ----- 2E16 Hz falls in that range
Answer:
A. 1:3
Explanation:
If we look at the ions shown in the image attached to the question, we will notice that we have aluminum (Al^3+), a trivalent ion combining with the iodide ion (I^-).
Aluminum can easily give out its three outermost electrons to three atoms of iodine. If aluminum gives out its three electrons, it achieves the stable octet structure. Iodine atoms have seven electrons in their outermost shell. They only need one more electrons to complete their octet. This one electron can be gotten by the combination of three iodine atoms with one atom of aluminum. One electron each is transferred from the aluminum atom to each iodine atom to form AlI3 with a ratio of 1:3.
