Answer:30 L
Explanation:
Initial Volume
=
V
1
=
60
l
i
t
e
r
Initial Temperature
=
T
1
=
546
K
Final Temperature
=
T
2
=
273
K
Final Vloume
=
V
2
=
?
?
Sol:-
Since the pressure is constant and the question is asking about temperature and volume, i.e,
V
1
T
1
=
V
2
T
2
⇒
V
2
=
V
1
⋅
T
2
T
1
=
60
⋅
273
546
=
60
2
=
30
l
i
t
e
r
⇒
V
2
=
30
l
i
t
e
r
Hence the new volume of the gas is
30
l
i
t
e
r
Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.
Since, 1 US gal=3.78 L
Volume of tank in L will be:
Also, 1 L=1000 mL
Thus,
Mass of gasoline can be calculated as follows:
m=d×V
Here, d is density and V is volume thus,
Therefore, mass of gasoline will be 
.
The Ecliptic is an imaginary line on the sky that marks the annual path of the sun. It is the projection of Earths orbit onto the celestial sphere. The ecliptic is even the starting point for the celestial coordinate system used by astronomers to pinpoint the location of every star, nebula, and galaxy.
Answer: <span>O₂(g), Br₂(l) Fe(s), He(g)
</span>
Justification:
1) The state variable given, ΔHf°, is <span>the standard
enthalpy of formation. By definition it is the change in the enthalpy that accompanies the
formation of a mole of compound in the standard state, from its
constituent elements in the standard state.
</span>
2) Since the standard state of <span>O₂(g), Br₂(l) Fe(s), He(g) is the very same shown, they do not evolve any heat for its formation. This is, that is the same state of the constituents, and no change is involved.
</span>
<span>That is why, </span><span>ΔHf°, of those elements is 0.
</span>
