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2 years ago

We desire to make an lc circuit that oscillates at 100 hz using an inductance of 2.5 h. we also need a capacitance of:______.

Physics

1 answer:

Vinil7 [7]2 years ago

7 0

The LC circuit will also need a capacitance of 1.01 μF.

<h3>What is capacitance?</h3>

Capacitance is the ratio of the amount of electric charge stored on a conductor to a difference in electric potential.

<h3>Capacitance needed for the resonance circuit</h3>

Xl = Xc

where;

Xl is the inductive reactance

Xl = ωL

Xc = 1/ωC

ωL = 1/ωC

ω²LC = 1

C = 1/(ω²L)

C = 1/(2πf)²(L)

C = 1/(4π²f² L)

C = 1/(4π² x 100² x 2.5)

C = 1.01 x 10⁻⁶ F

C = 1.01 μF

Thus, the LC circuit will also need a capacitance of 1.01 μF.

Learn more about capacitance here: brainly.com/question/13578522

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3 years ago

200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?

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Explanation:

Given parameters:

Work done = 200J

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Amount of force applied =?

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The unit of work done is in joules

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4 years ago

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3 years ago

Read 2 more answers

Xenon has an enthalpy of vaporization of 12.6 kJ/mol and a vapor pressure of 1.00 atm at –108.0 °C. What is the vapor pressure o

earnstyle [38]

Answer:

P₁ = 0.0562 atm

Explanation:

Using the Clausius-Clapeyon equation

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁) ------ (eqn 1)

Step 1: From the question given, we state out the parameters given

P₁ = ? T₁ = -148.0⁰C

P₂ = 1atm T₂ = -108.0⁰C

ΔHvap = 12.6kJ/mol R = 8.314J/K.mol

Step 2: Do conversions where necessary for unit consistency since our R value is in J/K.mol

a) convert ⁰C to K

1K = ⁰C + 273.15

T₁ = -148.0⁰C => -148.0⁰C + 273.15

T₁ = 125.15K

T₂ = -108.0⁰C => -108.0⁰C + 273.15

T₂ = 166.15K

b) convert kJ/mol to Joules

ΔHvap = 12.6kJ/mol = 12600Joules

substituting parameters into eqn 1

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)

ln (P₁/1atm) = 12600J / 8.314 (1/166.15 - 1/125.15)

= 1515.51 (0.0060 - 0.0079)

= 1515.51(-0.0019)

ln (P₁/1atm) = -2.8794

taking exponential of both sides to get rid of the natural log

P₁ = e^ -2.8794

P₁ = 0.05616 atm

P₁ = 0.0562atm

Key Words

1) Clausius-Clapeyon: shows the relationship between pressure and temperature and it is used to estimate the vapour of a solution at a different temperature

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3 years ago

A superball and a clay ball are dropped from a height of 10cm above a tabletop. They have the same mass 0.05kg and the same size

Olenka [21]

Answer:4.08 N

Explanation:

Given data

superball dropped from a height of 10 cm

Mass of ball $\left ( m\right )$ =0.05kg

time of contact $\left ( t\right )$ =34.3 $\times 10^{-3}$ s

Now we know impulse = $Force\times time\ of\ contact$ =Change in momentum

$F_{average}\times t$ = $m\left ( v-(-v)\right )$

and velocity at the bottom is given by

v= $\sqrt{2gh}$

$F_{average}\times 34.3\times 10^{-3}$ = $0.05\left ( 1.4-(-1.4)\right )$

$F_{average}$ =4.081N

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3 years ago