The kinetic energy at the bottom of the swing is also 918 J.
Assume the origin of the coordinate system to be at the lowest point of the pendulum's swing. A pendulum, when raised to the highest point has potential energy since it is raised to a height h above the origin. At the highest point, the pendulum's velocity becomes zero, hence it has no kinetic energy. Its energy at the highest point is wholly potential.
When the pendulum swings down from its highest position, it gains velocity. Hence a part of its potential energy begins to convert itself into kinetic energy. If no dissipative forces such as air resistance exist, then, the law of conservation of energy can be applied to the swing.
Under the action of conservative forces, the total mechanical energy of a system remains constant.This means that the sum of the potential and kinetic energies of a body remains constant.
When the pendulum reaches the lowest point of its swing, it is at the origin of the chosen coordinate system. Its vertical displacement from the origin is zero, hence its potential energy with respect to the origin is zero. Therefore the entire potential energy of 918 J should have been converted into kinetic energy, according to the law of conservation of energy.
Thus, the kinetic energy of the pendulum at the lowest point of its swing is equal to the potential energy it had at its highest point, which is equal to <u>918 J.</u>
Answer:
(a) 4190 rad/sec
(b) 4064 rad/sec
(c) Percentage change is 3 %
Explanation:
We have given inductance
Capacitance
We know that resonance frequency is given by
Now resistance is given as R = 1020 ohm '
(b) We know that damped frequency is given by
(c) Percentage change in frequency %
This drag force is always opposite to the object's motion, and unlike friction between solid surfaces, the drag force increases as the object moves faster.
Answer:
4.9 kg.m/s.
Explanation:
Given that
mass ,m = 0.7 kg
Initial speed , u = 5 m/s ( Towards + x direction)
Final speed ,v= -2 m/s ( Towards - x direction)
We know that linear momentum is given as
P = Mass x velocity
Change in the linear momentum ΔP will be
ΔP = m ( v - u)
Now by putting the values in the above equation ,we get'
ΔP= 0.7 ( -2 - 5 ) kg.m/s
ΔP= - 4.9 kg.m/s
The magnitude of the change in the linear momentum will be 4.9 kg.m/s.
<span>So we want to know why the does a bouncing ball rise to a lower height with each bounce. So lets say the ball is first on some height h. There it has potential energy Ep=m*g*h. Then as the ball starts falling to the ground the energy converts to kinetic energy Ek=(1/2)*m*v^2. When the ball falls to the ground, the kinetic energy transforms to elastic energy because the ball deforms as it hits the ground and some small quantity of heat. The heat goes to the air and to the ground so it gets removed from the system. So there is less energy in the system to be converted back to kinetic energy as the ball starts to rise in height again. Thats why the ball is not able to get bact to the same height as it started from. </span>