While Earth is only the <u>fifth largest planet in the solar system</u>, it is <u>the only world </u>in <u>our solar system</u> with the life we know or are starting to know of, for example, us as human beings. Just slightly larger than nearby Venus, Earth is the biggest of the four planets closest to the Sun, all of which are made of rock and metal. Other planets such as Jupiter are not so likely to have life like us there, for it is full of gas we don't breathe, and gases which are harmful to us, unlike the oxygen we have here on earth.
Answer:
The air resistance on the skydiver is 68.6 N
Explanation:
When the skydiver is falling down, there are two forces acting on him:
- The force of gravity, of magnitude 
, in the downward direction (where m is the mass of the skydiver and g is the acceleration due to gravity)
- The air resistance, 
, in the upward direction
So the net force on the skydiver is:
where
m = 7.0 kg is the mass
According to Newton's second law of motion, the net force on a body is equal to the product between its mass and its acceleration (a):
In this problem, however, the skydiver is moving with constant velocity, so his acceleration is zero:
Therefore the net force is zero:
And so, we have:
And so we can find the magnitude of the air resistance, which is equal to the force of gravity:
Answer:
Net force equals 0
Explanation:
Newton's first law states that an object at rest tends to remain at rest, and an object in motion tends to remain in motion with a constant velocity (constant speed and direction of motion), unless it is acted on by a nonzero net force. Note that the net force is the sum of all the forces acting on an object.
Assuming that the voltage is constant, and the resistance was doubled, since I=V/R, the current through the circuit will be halved. As P=IV, with the same voltage and halved current, the power dissipated by the circuit will be halved
Answer:
From point A to point D is 20
The final displacement is 32
Explanation:
AB=8
BC=8
CD=4
DE=8
EF=4
DE= 8 because the object moves 4 meters in each direction.
AB+BC+CD=20(A to D)
AB+BC+CD+DE+EF=32(Final displacement)
