Answer:
(a) 5.7 s
(b) 39 m/s
Explanation:
(a) u = 18 m/s
At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.
use first equation of motion.
v = u + g t
0 = 18 - 10 x t
t = 1.8 s
Let the maximum height attained by the ball when it thrown from 50 m height is h'.
Use third equation of motion
v^2 = u^2 + 2 g h'
0 = 18^2 - 2 x 10 x h'
h' = 16.2 m
Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m
Let t' be the time taken by the ball to hit the ground as it falls from maximum height.
use third equation of motion
H = ut + 1/2 x g t'^2
76.2 = 0 + 1/2 x 10 x t'^2
t' = 3.9 s
Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s
(b) Let v be the velocity with which the ball strikes the ground.
v^2 = u^2 + 2 g H
v^2 = 0 + 2 x 10 x 76.2
v = 39 m/s
The answer would be to research the need. This should have been done before the project began.
Answer:
Explanation:
We know that:
where 
is the initial energy, 
is the final energy and 
is the energy lost due to friction.
so:
Where M is the mass and V is the velocity of the runner, so:
Answer:
<h2>
<u>3. The Sputnik orbitted at approximately 577.1 km above the surface of the Earth. </u></h2><h2>
<u>4.First Successful U.S. Rocket Launch into Space was The Jupiter C</u></h2>
Explanation:
The first two are already answered 5-9 I cannot answer because I have not watched "October sky video" and I don't know who homer and the boys are<em>.</em>
I Hope This helps
