Given Information:
Power = P = 100 Watts
Voltage = V = 220 Volts
Required Information:
a) Current = I = ?
b) Resistance = R = ?
Answer:
a) Current = I = 0.4545 A
b) Resistance = R = 484 Ω
Explanation:
According to the Ohm’s law, the power dissipated in the light bulb is given by

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.
Re-arranging the above equation for current I yields,

Therefore, 0.4545 A current is flowing through the light bulb.
According to the Ohm’s law, the voltage across the light bulb is given by

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.
Re-arranging the above equation for resistance R yields,

Therefore, the resistance of the bulb is 484 Ω
The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.
<h3 /><h3>What is temperature?</h3>
Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.
If the given turbine is assumed to be reversible;
(Initial pressure)=60 mpa = 60 bar
(Initial temperature)=600° C
(Exit pressure)=600 kpa=6 bar
The heat balance equation is;

The change in the entropy is;

The work done by the turbine is;

Hence,the work done by the turbine will be 708.2 kJ/kg.
To learn more about the temperature, refer to the link;
brainly.com/question/7510619
#SPJ4
Answer:
Do find the answer in the attachment herein.
Explanation:
From the attached diagram:
I. Activation energy = Activated complex - ∆H(reactants)
Activation energy = 162-140 = 22Kj.
II. ∆H(reaction) = ∆H(products) - ∆H(reactants)
∆H(reaction) = 37 - 140 = -103Kj.
I’ve answered this before so I know the question is missing an
important given and that given is: <span>1 has an
empty trailer and the other has a fully loaded one.
So, it would be the fully loaded trailer that would take a longer distance to
stop because a lot of weight is being pulled, and when the brakes are started,
the fully loaded trailer is more like pushing against the truck.</span>