Answer:
0.43 m
Explanation:
Angle of incident and angle of reflection is same.
tan Θh = L' / x (eye)
L' = Length of the window
x (eye) = Distance of the mirror from the eye
tan Θh = L / (x (eye) + xw)
xw = Distance of the mirror from the window
L'/ x (eye) = L / ( x (eye) + xw)
L' = L*x (eye) / ( x (eye) + xw)
L' = (2*0.5) / (0.5 + 1.8)
L' = 0.43 m
Answer: The current must be equal to 
amps, or ~0.9574 amps.
Explanation:
You can find the current in amperes using ohms and watts from this formula:
Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.
You can then substitute 60 and 55 into the equation to find I:
Then, simplify the denominator:
Rationalize the denominator:
Simplify the numerator by finding its factors:
The current must be equal to amps, or ~0.9574 amps.
Answer:
v = 10 V and E = 2 10³ N/C
Explanation:
The electrical potentials and the electric field at one point are related by the expression
ΔV = - ∫ E. dS
Where the bold indicates vector quantities, E is the electric field and S is the line of displacement of the load, in general displacement is perpendicular to the equipotential lines, which reduces the product scales to the ordinary product.
If the potential difference is the most usual that is V = 10 V, the electric field is
s = 0.5 cm = 0.5 10⁻² m
E = ΔV / S
E = 10/0.5 10⁻²
E = 2 10³ N / C
If the award weighs 200 newtons and 200 newtons equals 44.96 pounds of force even though it is of such a force if it hits the ground the energy will either discharge into the air doing nothing but creating a loud sound or it will discharge into the ground altering the ground that it landed on.
Hope this helps :)
Answer:
The intensity at a spot 71 m away is 
Explanation:
Given:
Initial intensity,
at a distance, 
Required:
New intensity, 
at a distance, 
Using the inverse square law,
I ∝ 
⇒
×
Thus, the intensity at a spot that is 71 m away is
