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3 years ago

14

How do you calculate the speed of a wave?

2 answers:

Anton [14]3 years ago

4 0

Answer:

Wave speed is the distance a wave travels in a given amount of time, such as the number of meters it travels per second. Wave speed is related to wavelength and wave frequency by the equation: Speed = Wavelength x Frequency. This equation can be used to calculate wave speed when wavelength and frequency are known.

Explanation:

Maksim231197 [3]3 years ago

4 0

Answer:

Speed = Wavelength x Frequency

Explanation:

Wave speed is the distance a wave travels in a given amount of time, such as the number of meters it travels per second. Wave speed is related to wavelength and wave frequency by the equation: Speed = Wavelength x Frequency. This equation can be used to calculate wave speed when wavelength and frequency are known.

I hope this helps!

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How long will it take a ball to roll 10 meters along the floor at a speed of 0.5 m/s?

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Answer:

20 seconds.

Explanation:

The following data were obtained from the question:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

The speed of an object is simply defined as the distance travelled by the object per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the time taken for the ball to travel a distance of 10 m as shown below:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

Speed = Distance /time

0.5 = 10/time

Cross multiply

0.5 × time = 10

Divide both side by 0.5

Time = 10/0.5

Time = 20 secs.

Therefore, it will take 20 seconds for the ball to travel a distance of 10 m.

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3 years ago

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

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Explanation:

It is given that,

Frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

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$d\ sin\theta=n\lambda$

For third maxima,

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{nc}{fd})$

$\theta=sin^{-1}(\dfrac{3\times 3\times 10^8\ m/s}{5\times 10^{14}\ Hz\times 2.2\times 10^{-5}\ m})$

$\theta=4.69^{\circ}$

(b) For second dark fringe, n = 2

$d\ sin\theta=(n+1/2)\lambda$

$\theta=sin^{-1}(\dfrac{5\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{5c}{2df})$

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2 years ago