Answer:
323 m/s²
Explanation:
Given:
x₀ = 0 m
y₀ = 0 m
x = 29500 cos 65°
y = 29500 sin 65°
v₀x = 1810 cos 20°
v₀y = 1810 sin 20°
t = 9.20
Find:
ax, ay, θ
First, in the x direction:
x = x₀ + v₀ t + ½ at²
29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²
25017 = 15648 + 42.32 ax
ax ≈ 221.4
And in the y direction:
y = y₀ + v₀ t + ½ at²
29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²
15633 = 5695 + 42.32 ay
ay ≈ 234.8
Therefore, the magnitude of the acceleration is:
a² = ax² + ay²
a² = (221.4)² + (234.8)²
a ≈ 322.7
Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².
Answer:
After a nucleus with 85 protons undergoes alpha decay, it has 83 protons.
Explanation:
In an alpha particle there are two protons
In the given substance's nucleus, there are total of 85 protons
After the decay, the proton number reduce
The current proton number after decay is
85 -2 = 83
After a nucleus with 85 protons undergoes alpha decay, it has 83 protons.
Answer:
D)
Explanation:
The Period-Luminosity relationship tells us that luminosity increases with the period, and of course the more luminosity a star has the more far away they can be seen, so from this we know that:
A) False since lower luminosities can be observed when they are close.
B) False since longer periods means higher luminosities
C) False since lower luminosities can be observed when they are close.
D) True: Variable stars with shorter periods have lower luminosities, so they can only be observed when they are close.
Answer:
c. Kinetic energy is conserved in all collisions .
Explanation:
the total kinetic energy of system of particles involved in the collision does changes .
kinetic energy is not conserved in all collisions because in some cases energy is converted to another form of energy that is heat etc .
Answer:
The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58
Explanation:
Given that,
Length of plates = 8 cm
Width = 5.52 cm
Distance = 1.99 cm
Dielectric constant = 2.6
Length = 4.4 cm
Potential = 0.8 V
We need to calculate the initial capacitance
Using formula of capacitance
Put the value into the formula
We need to calculate the final capacitance
Using formula of capacitance
Put the value into the formula
We need to calculate the ratio of the new potential energy to the potential energy before the insertion of the dielectric
Using formula of energy
Put the value into the formula
Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58
