Flammability
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Answer:
volume = 972.23ml
Explanation:
using general gas law
P1V1/T1 = P2V2/T2
765 x 585/293 = 443 x V2/282
1527.39 =443 x V2/282
1527.38 x 282 = 443 x V2
430695.78 = 443 x V2
V2 = 430695.68/443
V2 = 972.23mL
Answer:
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Balanced equation
Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄
<h3>Further explanation</h3>
Given
Reaction
Mg3(PO4)2 + Al(NO3)3 → Mg(NO3)2 + AlPO4
Required
Balanced equation
Solution
Give a coefficient :
Mg₃(PO₄)₂ + aAl(NO₃)₃ → bMg(NO₃)₂ + cAlPO₄
Make an equation :
Mg, left = 3, right=b⇒b=3
P, left=2, right=c⇒c=2
Al, left=a, right=c⇒a=c⇒a=2
The reaction becomes :
Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄
