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Savatey [412]
3 years ago
13

The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

3H8(g)+5O2(g)⟶3CO2(g)+4H2O(g) How many grams of O 2 ( g ) O2(g) are needed to completely burn 17.9 g C 3 H 8 ( g ) ?
Chemistry
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

65.1g of O2 will be needed

Explanation:

The equation for the reaction is given below:

C3H8 + 5O2 —>3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of O2 = (16x2) = 32g/mol

Mass conc. of O2 from the balanced equation = 5 x 32 = 160g

From the above calculations, we can easily find the mass of O2 needed to completely burn 17.9 g C3H8. This can be done by the following:

From the equation,

44g of C3H8 was completely burnt by 160g of O2.

Therefore,

17.9g of C3H8 will be burnt by Xg of O2. i.e

Xg of O2 = (17.9x160) / 44 = 65.1g

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1. A cell must continuously sort useful materials from its waste products and then remove or recycle the waste. One way a cell d
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Based on the role of ubiquitin in protein deconstruction as stated in the passage, the correct options are as follows:

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<h3>What are phrases?</h3>

Phrases refers to a group of words which contains a verb but which on their own do not make complete sense.

In the description of the role of Ubiquitin, it is described as a small polypeptide chain containing 76 amino acids. The main tole of ubiquitin is to tag proteins for deconstruction in the proteasomes.

Therefore, the phrase describes the purpose of ubiquitin is to tag waste proteins for recycling in the proteasomes; option A.

Based on the passage, the statement that describes the overall consequence of proteins containing mutations is: Wastes will build up in vital organs, and the organism will experience disease; option D

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The decomposition time : 7.69 min ≈ 7.7 min

<h3>Further explanation</h3>

Given

rate constant : 0.029/min

a concentration of  0.050 mol L  to a concentration of 0.040 mol L

Required

the decomposition time

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time

For first-order reaction :

[A]=[Ao]e^(-kt)

or

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Input the value :

ln(0.040)=-(0.029)t+ln(0.050)

-3.219 = -0.029t -2.996

-0.223 =-0.029t

t=7.69 minutes

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