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Slav-nsk [51]
1 year ago
12

For an object being launched at ground level at a tilted non-zero initial velocity, is the velocity zero anywhere? are the horiz

ontal or vertical components of the velocity zero at any point?
Physics
1 answer:
borishaifa [10]1 year ago
3 0

The correct answer No the velocity is not zero anywhere For an object being launched at ground level at a tilted non-zero initial velocity, and horizontal or vertical components of the velocity is zero at maximum height .

Because velocity is a vector (it has magnitude and direction), the overall velocity of an object can be calculated by adding the x and y components: v2 = vx2 + vy2. Meters are used to express horizontal and vertical distances (m). The horizontal velocity component (vx) describes the effect of velocity on horizontal displacement of the projectile.

The vertical velocity component (vy) describes the effect of velocity on vertical displacement of the projectile. The vertical component of a projectile's velocity is momentarily zero (vy = 0 m/s) when it reaches maximum height. The horizontal component of its velocity, however, is not zero.

Learn more about components of velocity here :-

brainly.com/question/12498991

#SPJ4

You might be interested in
A 70 kg student jumps down to form a 1 m high platform. She forgets to bend her knees and her downward motion stops in 0.02 seco
34kurt

Answer:

15,505 N

Explanation:

Using the principle of conservation of energy, the potential energy loss of the student equals the kinetic energy gain of the student

-ΔU = ΔK

-(U₂ - U₁) = K₂ - K₁ where U₁ = initial potential energy = mgh , U₂ = final potential energy = 0, K₁ = initial kinetic energy = 0 and K₂ = final kinetic energy = 1/2mv²

-(0 - mgh) = 1/2mv² - 0

mgh = 1/2mv² where m = mass of student = 70kg, h = height of platform  = 1 m, g = acceleration due to gravity = 9.8 m/s² and v = final velocity of student as he hits the ground.

mgh = 1/2mv²

gh = 1/2v²

v² = 2gh

v = √(2gh)

v = √(2 × 9.8 m/s² × 1 m)

v = √(19.6 m²/s²)

v = 4.43 m/s

Upon impact on the ground and stopping, impulse I = Ft = m(v' - v) where F = force, t = time = 0.02 s, m =mass of student = 70 kg, v = initial velocity on impact = 4.43 m/s and v'= final velocity at stopping = 0 m/s

So Ft = m(v' - v)

F = m(v' - v)/t

substituting the values of the variables, we have

F = 70 kg(0 m/s - 4.43 m/s)/0.02 s

= 70 kg(- 4.43 m/s)/0.02 s

= -310.1 kgm/s ÷ 0.02 s

= -15,505 N

So, the force transmitted to her bones is 15,505 N

3 0
3 years ago
A diamond with a mass of 45 g hangs motionless from a chain. what is the upward force of the chain on the diamond?
BARSIC [14]
The upward force of the chain on the diamond would be the tension in the chain, and this tension would have to support the weight of the 45g that hangs from the chain.

mass = 45 g = 45/1000 kg = 0.045kg

Weight = mg = 0.045 * 10 ≈ 0.45N,            g ≈ 10 m/s²

So the upward force is ≈ 0.45N. 
7 0
4 years ago
Describe an experiment to verify the principle of moments
Ludmilka [50]

The principle of moment can be verified when two known masses are suspended on a uniform meter rule.

<h3>What is principle of moment?</h3>

The principle of moment states that, the sum of clockwise moment is equal to the sum of the anticlockwise moment.

The principle of moment is verified when two known mass (m1 and m2) are suspended on a uniform meter rule.

The clockwise moment will be equal anticlockwise moment of the two masses.

(m_1g )r_1 = (m_2g)r_2

Thus, the principle of moment can be verified when two known masses are suspended on a uniform meter rule.

Learn more about principle of moment here: brainly.com/question/20298772

5 0
3 years ago
What is the gravitational attraction on you due to a mountain with a mass of 100 million metric tons 1 km away ?
nikklg [1K]

The magnitude of the gravitational attraction is 4\cdot 10^{-4} N.

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, we have

m_1 = 60 kg is my mass

The mass of the mountain is 100 million tons, and keeping in mind that

1 ton = 1000 kg

The mass of the mountain is

m_2 = 100 \cdot 10^6 tons =100 \cdot 10^6 tons \cdot (1000 kg/ton)=100\cdot 10^9 kg

The distance between me and the mountain is

r = 1 km = 1000 m

Therefore, the gravitational attraction is

F=\frac{(6.67\cdot 10^{-11})(100\cdot 10^9)(60)}{(1000)^2}=4\cdot 10^{-4} N

Learn more about gravitational force here:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
Which of these os true? (A)light travels in a straight line.(B)light travels in a random manner. (C) parallel beams are divergen
jok3333 [9.3K]

Answer:

light travels in a straight line

Explanation:

the others are wrong

6 0
3 years ago
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