The Earth heats up, the cloud coverage acting as a blanket to raise the general areas temperature.
There is a missing data in the text of the problem: the current drawn is 0.5 A (found on internet)
Solution:
The power used by the toaster is the product between the voltage V and the current I:
The toaster is used for a time of 2 hours: t=2h, therefore the energy used is equal to
A silica-rich igneous rock that has large crystals and makes up much of the continental crust is called granite. These rocks are usually pink, gray or white in color depending on the minerals found on the rock. Generally, granite would have a range of 20% to 60% by volume of quartz and a minimum of 35% feldspar. This rock is a result from volcanic arcs and from the collision of continental masses. Due to its abundance, it has been used in a number of applications. It is used as an aggregate and filler in roading and construction industries. It is also cut and polished to be used in foyers, building facings, bench counters and tops.
The second diver have to leap to make a competitive splash by 4.08 m high.
<h3>What is potential energy?</h3>
The energy by virtue of its position is called the potential energy.
PE = mgh
where, g = 9.81 m/s²
Given is the diver jumps from a 3.00-m platform. one diver has a mass of 136 kg and simply steps off the platform. another diver has a mass of 100 kg and leaps upward from the platform.
The potential energy of the first diver must be equal to the second diver.
P.E₁ = P.E₂
m₁gh₁ = m₂gh₂
Substitute the vales, we have
136 x 3 = 100 x h₂
h₂ = ₂4.08 m
Thus, the second diver need to leap by 4.08 m high.
Learn more about potential energy.
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Answer:
U = 0.413 J
Explanation:
the potential energy between two charges q1 and q2 is given by the following formula:
(1)
k: Coulomb's constant = 8.98*10^9 NM^2/C^2
q1: first charge = 4.6 μC = 4.6*10^-6 C
q2: second charge = 1.0 μC*10^-6 C
r: distance between charges = 10.0 cm = 0.10 m
You replace the values of all variables in the equation (1):
Hence, the energy between charges is 0.413 J
