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Slav-nsk [51]
3 years ago
5

(Timed) Did I get this physics question right?

Physics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

yes

Explanation:

yes that's correct

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9. How does the length of the hypotenuse in a right triangle relate to the lengths of the legs? (2 points)
konstantin123 [22]
<span>The pythagorean theorem addresses the length of the hypotenuse in relation to the length of the legs. The square root of the length of the hypotenuse is equal to the sum of one leg squared plus the other leg squared. In other words, A squared plus B squared equals C squared where A and B are the lengths of the legs of the triangle and C is the length of the hypotenuse.</span>
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3 years ago
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Which situation describes a system with decreasing gravitational potential energy?
lord [1]

Answer: a boy jumping down

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What type of glass absorbs light and does not allow light to pass through it?
sesenic [268]

opaque glass does not allow light to pass through it.

8 0
3 years ago
_______ is a vector quantity; ________ is a scalar quantity.
jasenka [17]

Answer: Velocity...Distance

Explanation: Velocity is a vector quantity as it has both magnitude and direction

Distance is a scalar quantity as it has only magnitude and no direction

hope this helped...

7 0
4 years ago
An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens.
CaHeK987 [17]

A) 11.1 cm

We can find the focal length of the lens by using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p = 16.0 cm is the distance of the object from the lens

q = 36.0 cm is the distance of the image from the lens (taken with positive sign since it is on the opposide side to the image, so it is a real image)

Solving the equation for f:

\frac{1}{f}=\frac{1}{16.0 cm}+\frac{1}{36.0 cm}=0.09 cm^{-1}\\f=\frac{1}{0.09 cm^{-1}}=11.1 cm

B) Converging

The focal length is:

- Positive for a converging lens

- Negative for a diverging lens

In this case, the focal length is positive, so it is a converging lens.

C) 18.0 mm

The magnification equation states that:

\frac{h_i}{h_o}=-\frac{q}{p}

where

h_i is the heigth of the image

h_o is the height of the object

q=36.0 cm

p=16.0 cm

Solving the formula for h_i, we find

h_i = -h_o \frac{q}{p}=-(8.00 mm)\frac{36.0 cm}{16.0 cm}=-18.0 mm

So the image is 18 mm high.

D) Inverted

From the magnification equation we have that:

- When the sign of h_i is positive, the image is erect

- When the sign of h_i is negative, the image is inverted

In this case, h_i is negative, so the image is inverted.

4 0
4 years ago
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