The circle below has center P, and its radius is 6in. Given that =m∠QPR170°, find the length of the major arc QSR.
1 answer:
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Answer:
147.5 km and 64.4 km
Step-by-step explanation:
a=120 km
b=70 km
β=28 degrees ( ∘)
b^2=(a^2)+(c^2)−2ac*cosβ
70^2 =(120^2 )+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )
(c^2 ) −211.907c+9500=0
note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use
p=1;q=−211.907;r=9500
D=(q^2 ) −4pr=(211.907^2 )−4⋅1⋅9500=6904.75561996
D>0
=
(−q±
)/2p=(211.91±
)/2
=105.95371114±41.5474295834
(−147.501140726)(
−64.4062815596)=0
=147.501140726
=64.4062815596