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zepelin [54]
1 year ago
7

An ideal parallel plate capacitor remains attached to a battery while the plates are moved closer together. during this process,

the magnitude of the electric field between the plates ______ .
Physics
1 answer:
xz_007 [3.2K]1 year ago
5 0

During this process, the magnitude of the electric field between the plates increases. For parallel conducting plates, V and E follow the formula E = V/d. The magnitude of ΔV = VAB. The following formula must be used to shift a charge from plate A with a greater potential to plate B with a lower potential: -ΔV = VA - VB = VAB.

Electric filed = V/d, move closed hence d is decreased and hence electric field will increase.

<h3>What is Electric potential?</h3>

The majority of the time, the electric field has an attribute called electric potential. Whether or whether a charge should be applied to the electric field is independent of reality.  All locations with a distance of r from point charge +q consistently have a comparable potential.

To learn more about Electric potential refer to the link:

brainly.com/question/12645463

#SPJ4

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lozanna [386]
Q2 is 1.60x10^-19.



because if you round up or add, you will come with q2
3 0
3 years ago
Read 2 more answers
The train with a mass of 49 kg × 10⁴ kg departs from the place and in 25 seconds reaches a speed of 5m / s, determine the attrac
mote1985 [20]

Answer:

Read this entry from a blog about service dogs.

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What is the secondary purpose of this blog?

to inform readers about seeing-eye dogs

to entertain readers with details about Lexie

to persuade readers to train service dogs

to convince readers to adopt Labrador retrievers

Explanation:

5 0
3 years ago
constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3
meriva

Answer:

W = 71J

Explanation:

Given force F = (5i+5j−1k)N

d = Δr

r1 = (−5,−3,−4)m

r2 = (2,5,0)m

Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))

Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m

W = F•d = (5i+5j−1k)•(7i+ 8j +4k)

W = 5×7 + 5×8 +-1×4 = 35 + 40 - 4

W = 71J

6 0
3 years ago
When an object is fully converted into energy the amount of energy liberated is
EleoNora [17]

Answer:

Mass, m = 4 kg

Explanation:

<u>Given the following data;</u>

Energy = 3.6 * 10^17 Joules

We know that the speed of light is equal to 3 * 10⁸ m/s.

To find the mass of the substance;

The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.

The equation illustrates, energy equals mass multiplied by the square of the speed of light.

Mathematically, the theory of special relativity is given by the formula;

E = mc^{2}

Where;

  • E is the energy possessed by a substance.
  • m is the mass.
  • c is the speed of light.

Substituting into the formula, we have;

3.6 * 10^{17} = m * 300000000^{2}

3.6 * 10^{17} = m * 9*10^{16}

m = \frac {3.6 * 10^{17}}{9*10^{16}}

Mass, m = 4 kg

8 0
3 years ago
Xenon has an enthalpy of vaporization of 12.6 kJ/mol and a vapor pressure of 1.00 atm at –108.0 °C. What is the vapor pressure o
earnstyle [38]

Answer:

P₁ = 0.0562 atm

Explanation:

Using the Clausius-Clapeyon equation

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)       ------ (eqn 1)

Step 1: From the question given, we state out the parameters given

P₁ = ?                T₁ = -148.0⁰C

P₂ = 1atm          T₂ = -108.0⁰C

ΔHvap = 12.6kJ/mol      R = 8.314J/K.mol

Step 2: Do conversions where necessary for unit consistency since our R value is in J/K.mol

a) convert ⁰C to K

1K = ⁰C + 273.15

T₁ = -148.0⁰C => -148.0⁰C + 273.15

T₁ = 125.15K

T₂ = -108.0⁰C => -108.0⁰C + 273.15

T₂ = 166.15K

b) convert kJ/mol to Joules

ΔHvap = 12.6kJ/mol = 12600Joules

substituting parameters into eqn 1

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)

ln (P₁/1atm) = 12600J / 8.314 (1/166.15 - 1/125.15)

                  = 1515.51 (0.0060 - 0.0079)

                  = 1515.51(-0.0019)

ln (P₁/1atm) = -2.8794

taking exponential of both sides to get rid of the natural log

P₁ = e^ -2.8794

P₁ = 0.05616 atm

P₁ = 0.0562atm

Key Words

1) Clausius-Clapeyon: shows the relationship between pressure and temperature and it is used to estimate the vapour of a solution at a different temperature

5 0
3 years ago
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