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3 years ago

As an object moves, the distance it travels increases with time. Agree Disagree

Physics

1 answer:

egoroff_w [7]3 years ago

3 0

Answer:

Agree

Explanation:

Distance is described as "how much ground an object is covered" in physics, and because the object is moving, no matter which direction, it is constantly gaining more distance. You can think of the object as a car, and as the car is moving down a highway it is gaining more and more distance as the seconds go by.

You might be confused with the term displacement, "how far out of place an object is" which in this case would be false.

Does that make sense?

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A piece of wood is floating in a tub of water. a second piece of wood rest on top of the first piece; it does not touch the wate

barxatty [35]

The water leval in the tub will stay the same due to the law of water replacement.

5 0

3 years ago

An open 1-m-diameter tank contains water at a depth of 0.7 m when at rest. As the tank is rotated about its vertical axis the ce

Mamont248 [21]

Answer:

Explanation:

To find the angular velocity of the tank at which the bottom of the tank is exposed

From the information given:

At rest, the initial volume of the tank is:

$V_i = \pi R^2 h_i --- (1)$

where;

height h which is the height for the free surface in a rotating tank is expressed as:

$h = \dfrac{\omega^2 r^2}{2g} + C$

at the bottom surface of the tank;

r = 0, h = 0

∴

$h = \dfrac{\omega^2 r^2}{2g} + C$

0 = 0 + C

C = 0

Thus; the free surface height in a rotating tank is:

$h=\dfrac{\omega^2 r^2}{2g} --- (2)$

Now; the volume of the water when the tank is rotating is:

dV = 2π × r × h × dr

Taking the integral on both sides;

$\int \limits ^{V_f}_{0} \ dV = \int \limits ^R_0 \times 2 \pi \times r \times h \ dr$

replacing the value of h in equation (2); we have:

$V_f} = \int \limits ^R_0 \times 2 \pi \times r \times ( \dfrac{\omega ^2 r^2}{2g} ) \ dr$

$V_f = \dfrac{ \pi \omega ^2}{g} \int \limits ^R_0 \ r^3 \ dr$

$V_f = \dfrac{ \pi \omega ^2}{g} \Big [ \dfrac{r^4}{4} \Big]^R_0$

$V_f = \dfrac{ \pi \omega ^2}{g} \Big [ \dfrac{R^4}{4} \Big] --- (3)$

Since the volume of the water when it is at rest and when the angular speed rotates at an angular speed is equal.

Then $V_f = V_i$

Replacing equation (1) and (3)

$\dfrac{\pi \omega^2}{g}( \dfrac{R^4}{4}) = \pi R^2 h_i$

$\omega^2 = \dfrac{4g \times h_i }{R^2}$

$\omega =\sqrt{ \dfrac{4g \times h_i }{R^2}}$

$\omega = \sqrt{\dfrac{4 \times 9.81 \ m/s^2 \times 0.7 \ m}{(0.5)^2} }$

$\omega = \sqrt{109.87 }$

$\mathbf{\omega = 10.48 \ rad/s}$

Finally, the angular velocity of the tank at which the bottom of the tank is exposed = 10.48 rad/s

6 0

3 years ago

A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.140 m2. The coil is now stretched to hav

DENIUS [597]

Answer:

Magnitude of induced emf will be 87.5 volt

Direction of induced emf will be clockwise

Explanation:

We have given number of turns in the coil N = 50

Initial area $A=0.140m^2$

Time is given dt = 0.1 sec

Magnetic field B = 1.25 T

From Faraday's law of electromagnetic induction

n $e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}$

$e=-50\times 0.140\times \frac{1.25}{0.1}=-87.5volt$

So magnitude of induced emf is 87.5 volt

Direction of induced emf will be clockwise

7 0

4 years ago

The fundamental frequency of a standing wave on a 1.0-m-long string is 440 Hz. What would be the wave speed of a pulse moving al

Nana76 [90]

Answer: v = 880m/s

Explanation: The length of a string is related to the wavelength of sound passing through the string at the fundamental frequency is given as

L = λ/2 where L = length of string and λ = wavelength.

But L = 1m

1 = λ/2

λ = 2m.

But the frequency at fundamental is 440Hz and

V = fλ

Hence

v = 440 * 2

v = 880m/s

4 0

3 years ago

How does the statement " silence is golden " relate to ethics in communicating at the workplace.?

Ipatiy [6.2K]

Answer:

Being silent most of the time is a good virtue under certain circumstances and environment. It is always advisable to remain quite silent and not be too quick to respond to situations or issues so as to avoid making and saying wrong words.

The ethics in a workplace involves communicating with others with less amount of talking as possible and more of body languages and signs. This is because the workplace is meant to be a serene place.

4 0

4 years ago