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1 year ago

Find the magnitude of this vector: 18.4 m -28.7 m magnitude

Physics

1 answer:

rjkz [21]1 year ago

7 0

The magnitude of this vector:

18.4 mi-28.7 mj is 34.09m

Given:

vector is

18.4 mi-28.7 mj

Magnitude = $\sqrt{18.4^2+28.7^2}=34.09$

This magnitude of a vector formula summarizes the distinct vector measures along the x-axis, y-axis, and z-axis. It is represented by the symbol |v|. A vector's magnitude is either a positive number or zero, and it can never be negative. Let us finally understand the magnitude of a vector formula by considering a few solved cases.

A vector's magnitude is equal to its length. The magnitude of the vector an is indicated by the symbol a. For further information on vector magnitude, see the introduction to vectors.

This article deduces formulas for the magnitude of vectors in two and three dimensions in terms of their coordinates. The magnitude formula for a two-dimensional vector a=(a1,a2)

To learn more about motion of gravity from the given link:

brainly.com/question/14033610

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3 years ago

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Nataliya [291]

Answer:

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Explanation:

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Solution:

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I = I_o * cos^2 (Q)

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Q = cos ^-1 (sqrt (I / I_o))

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3 years ago

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Answer;

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