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1 year ago

Find the magnitude of this vector: 18.4 m -28.7 m magnitude

Physics

1 answer:

rjkz [21]1 year ago

7 0

The magnitude of this vector:

18.4 mi-28.7 mj is 34.09m

Given:

vector is

18.4 mi-28.7 mj

Magnitude = $\sqrt{18.4^2+28.7^2}=34.09$

This magnitude of a vector formula summarizes the distinct vector measures along the x-axis, y-axis, and z-axis. It is represented by the symbol |v|. A vector's magnitude is either a positive number or zero, and it can never be negative. Let us finally understand the magnitude of a vector formula by considering a few solved cases.

A vector's magnitude is equal to its length. The magnitude of the vector an is indicated by the symbol a. For further information on vector magnitude, see the introduction to vectors.

This article deduces formulas for the magnitude of vectors in two and three dimensions in terms of their coordinates. The magnitude formula for a two-dimensional vector a=(a1,a2)

To learn more about motion of gravity from the given link:

brainly.com/question/14033610

#SPJ9

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2 years ago

An airplane flies horizontally at constant speed in a straightline direction. Its state of motion is unchanging. In other words

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Answer:

sum of all forces on the air plane must be ZERO

So both forces must be of same magnitude

Explanation:

As we know that airplane is moving with uniform speed is horizontal plane is a straight line

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So we will have

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now by Newton's law

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3 years ago

A mass of 13kg stretches a spring 14cm. The mass is acted on by an external force of 6sin(t/2)N and moves in a medium that impar

m_a_m_a [10]

Answer:

$13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\$

#Where $u$ is in meters and $t$ in seconds.

Explanation:

Given that : $m=13.0kg, \ L=0.14m, \ F(t)=6sin\frac{t}{2}N, F_d(t*)=-4N^{-1}, u\prime(t*)=0.12m/s\\u(0)=0,u\prime(0)=0.04m/s$

From $\omega=kL$ we have:

$k=\frac{\omega}{L}=\frac{mg}{0.14m}=\frac{13.0\times 9.8m/s}{0.14m}\\\\k=910kg/s^2$

From $F_d(t)=-\gamma u\prime(t)$ we have that:

$\gamma=-\frac{F_d(t*)}{u\prime(t*)}=\frac{4N}{0.12m/s}\\=33.33Ns/m$

Now,given that the initial value problem is given by:

$13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\$

Hence,the position of u at time t is given by

$13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\$ , $u$ in meters, $t$ in seconds.

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3 years ago

Describe the difference between a conductor and an insulator in terms of thermal energy transfer and provide an example of each.

Nikitich [7]

The difference between conductors and insulators is because of electronic structure of atoms and molecules.

Anywhere we have free electrons, we have a hard conductor where free electrons help in conduction.

In electrolytes, charged Ions do conduction.

Dielectrics (or insulators) don't have free electrons current.

Free electrons mean, the electrons that are not related with a specific atom, they are allowed to move nearby the crystal lattice.

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3 years ago

What force is required to cause a 5 kg bowling ball to accelerate at 4 m/s2

Scorpion4ik [409]

Answer:

20 N

Explanation:

By Newton's 2nd law,

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By that you can get the equation,

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3 years ago