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3 years ago

14

What is the relationship between potential and kinetic energy in chemical reactions?

1 answer:

astraxan [27]3 years ago

3 0

Answer:

2 and 3

Explanation:

because that's how kinetic and potential energy work

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A thermometer is placed directly sunlight will it read the temperature of the air or of the sun or of something else??

Norma-Jean [14]

It will read the temperature of the atmosphere.It is unable to read the temperature of the sun because some of the heat energy from the sun is absorbed by the layer of air molecules on Earth.

7 0

3 years ago

A model rocket rises with constant acceleration to a height of 4.2 m, at which point its speed is 27.0 m/s. How much time does i

geniusboy [140]

Answers:

a) $t=0.311 s$

b) $a=86.847 m/s^{2}$

c) $y=1.736 m$

d) $V=17.369 m/s$

Explanation:

For this situation we will use the following equations:

$y=y_{o}+V_{o}t+\frac{1}{2}at^{2}$ (1)

$V=V_{o} + at$ (2)

Where:

$y$ is the <u>height of the model rocket at a given time</u>

$y_{o}=0$ is the i<u>nitial height </u>of the model rocket

$V_{o}=0$ is the<u> initial velocity</u> of the model rocket since it started from rest

$V$ is the <u>velocity of the rocket at a given height and time</u>

$t$ is the <u>time</u> it takes to the model rocket to reach a certain height

$a$ is the <u>constant acceleration</u> due gravity and the rocket's thrust

<h2>a) Time it takes for the rocket to reach the height=4.2 m</h2>

The average velocity of a body moving at a constant acceleration is:

$V=\frac{V_{1}+V_{2}}{2}$ (3)

For this rocket is:

$V=\frac{27 m/s}{2}=13.5 m/s$ (4)

Time is determined by:

$t=\frac{y}{V}$ (5)

$t=\frac{4.2 m}{13.5 m/s}$ (6)

Hence:

$t=0.311 s$ (7)

<h2>b) Magnitude of the rocket's acceleration</h2>

Using equation (1), with initial height and velocity equal to zero:

$y=\frac{1}{2}at^{2}$ (8)

We will use $y=4.2 m$ :

$4.2 m=\frac{1}{2}a(0.311)^{2}$ (9)

Finding $a$ :

$a=86.847 m/s^{2}$ (10)

<h2>c) Height of the rocket 0.20 s after launch</h2>

Using again $y=\frac{1}{2}at^{2}$ but for $t=0.2 s$ :

$y=\frac{1}{2}(86.847 m/s^{2})(0.2 s)^{2}$ (11)

$y=1.736 m$ (12)

<h2>d) Speed of the rocket 0.20 s after launch</h2>

We will use equation (2) remembering the rocket startted from rest:

$V= at$ (13)

$V= (86.847 m/s^{2})(0.2 s)$ (14)

Finally:

$V=17.369 m/s$ (15)

5 0

3 years ago

A 700 kg racecar slowed from 30 m/s to 15 m/s. What was the change in momentum?

xxMikexx [17]

Momentum equation is

change in momentum = mass•initial velocity•final velocity

so....

p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!

8 0

3 years ago

What is environmental cleanliness

maw [93]

Answer:

it's the condition of the Earth to become neat and organized. it will give negative impact on the society and teach people to clean to have a better world to stay

8 0

3 years ago

An isolated conducting sphere has a 12 cm radius. One wire carries a current of 1.0000049 A into it while another wire carries a

tatuchka [14]

Answer:

it will take for the sphere to increase in potential by 1500 V, 503.71 s.

Explanation:

The charge on the sphere after t seconds is:

q = (1.0000049 - 1.0000000) t = 0.0000049 t

The voltage on the surface is

V = k * $\frac{q}{R}$ = k 0.0000049 t / R

solve for t

t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * $9e^{9}$ ) = 503.71 s

7 0

4 years ago