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mafiozo [28]
3 years ago
14

What is the relationship between potential and kinetic energy in chemical reactions?

Physics
1 answer:
astraxan [27]3 years ago
3 0

Answer:

2 and 3

Explanation:

because that's how kinetic and potential energy work

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3.5-m-diameter merry-go-round is rotating freely with an angular velocity of 0.78 rad/s . Its total moment of inertia is 1710 kg
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Use newton's method to find the second and third approximation of a root of
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Please answer this question 

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A power station with an efficiency e generates W watts of electric power and dissipates D J of heat energy each second to the co
Andrews [41]

Answer: 13.94 tons/s

Explanation:

On adding heat energy to a substance, the temperature would be changed by a particular amount. This relationship between heat energy and temperature is often different for each material. The specific heat, is a value that describes how they relate.

Heat energy = mass flow rate * specific heat * Δ T

Q = MC (ΔΦ)

Heat energy, Q= 3.5*10^8J

Mass flow rate, M= ?

Specific heat, C= 4184j/KgC

Change in temperature, ΔΦ= 6°C

M = Q/CΔΦ

M = (3.5*10^8)/4184*6

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3 0
3 years ago
Which of the following is considered to be a vector? 
AVprozaik [17]

Answer: B) Velocity

Explanation:

Velocity is a vector quantity. Velocities have both magnitude and direction.

8 0
3 years ago
Read 2 more answers
3. Two balls are rolling toward each other. One has a momentum of 85kg*m/s, and the other has a momentum of -85kg*m/s. What will
irakobra [83]

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

(P_{1})-(P_{2})=P_{3}

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

(85) - 85 = P_{3}\\P_{3}= 0

There is no movement of any of the balls, they remain at rest after the impact.

5 0
2 years ago
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