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Marina86 [1]
2 years ago
7

5.Calculate the number of moles of 18.0 dm3 of carbon monoxide (CO) at rtp.

Chemistry
1 answer:
jolli1 [7]2 years ago
7 0

Answer:

0.81mole

Explanation:

Given:

Volume of carbon monoxide  = 18dm³

Unknown

Number of moles of carbon monoxide  = ?

Solution:

To solve this problem;

           1 mole of any gas at rtp occupies a volume of 22.4dm³  

So;

           x mole of carbon monoxide will occupy a volume of 18dm³ at rtp

        22.4x  = 18

                x  = \frac{18}{22.4}   = 0.81mole

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kap26 [50]
  • Convert Kelvin to °c

(a) 67°c

Formula:-

k=°c+273

°c = 273 - k

°c = 273-67= 206 °c

(b) 1671 k

k=°c+273

°c = 273 - k

°c= 273-1671 = -1398°c

8 0
2 years ago
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sveta [45]

Answer:

E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)

Explanation:

Which ONE of the following is an oxidation–reduction reaction?

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8 0
3 years ago
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Scorpion4ik [409]

Answer:

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Explanation:

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3 years ago
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A.

Explanation:

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