Question

5.Calculate the number of moles of 18.0 dm3 of carbon monoxide (CO) at rtp.

Answer 1

Answer:

0.81mole

Explanation:

Given:

Volume of carbon monoxide  = 18dm³

Unknown

Number of moles of carbon monoxide  = ?

Solution:

To solve this problem;

           1 mole of any gas at rtp occupies a volume of 22.4dm³  

So;

           x mole of carbon monoxide will occupy a volume of 18dm³ at rtp

        22.4x  = 18

                x  = $\frac{18}{22.4}$   = 0.81mole