Answer:
The student should weigh out 61.2g of ethanolamine [6.12 * 10]
Explanation:
In this question, we are expected to calculate the mass of ethanolamine needed to make 60.0ml of it given that the density of the ethanolamine in question is 1.02g/cm^3
Mathematically, it has been shown that mass = density * volume
Hence, by multiplying the density by the volume, we get the mass.
Now, from the question we can see that we have the values for the density and the volume. We now need to get the mass.
Since cm^3 is same as ml, we need not perform any conversion.
Hence, the needed mass is:
60 * 1.02 = 61.2g
Water that contains large amounts of disolved salts
Answer:
S+ F2 ⇒ SF
S=1
F =2
So S +F2 ......... 2SF
2S + F2 ..........2SF this is a balance equation
S=2 F=2 in left side s=2 F = 2 in rightside
Explanation:⇆
⇒
Matter is made up of particles that are constantly moving. All particles have energy, but the energy varies depending on the temperature the sample of matter is in.
