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weeeeeb [17]
1 year ago
6

An enzyme works best at 98.6°f. the equation used to describe it requires the temperature to be in k. what is the correct tempe

rature? use (f×0.555) 255.37=k or (k−255.37)×1.8=f. 37 k 37 k 236 k 236 k 310 k 310 k 482 k
Physics
1 answer:
Marina86 [1]1 year ago
5 0

310.093k.

Given,

Best temperature for enzymes to work = 98.6°F

Unknown :

We need to convert the temperature from fahrenheit to kelvin.

Writing down the equation to be used in the problem's solution correctly:

K = (F x 0.55) + 255.37

F = (K - 255.37) x 1.8

The temperatures are expressed in kelvin (K) and fahrenheit (F), respectively.

There first equation would be significantly more quicker to use :

K = (98.6 x 0.555) + 255.37

= 54.723 + 255.37

= 310.093K

➤ The activity and rate of an enzyme reaction typically increase with temperature, while a decrease in temperature slows the enzymatic reaction. Each enzyme's activity peaks at its individual optimum temperature, and it decreases above and below that point.

Find more on enzymes at : brainly.com/question/1596855

#SPJ4

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A gun shoots a bullet with a velocity of 500 m/s. The gun is aimed horizontally and fired from a height of 1.5 m. How far does t
MrMuchimi

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity u_x. It takes a time <em>t</em> to fall a vertical distance <em>y</em> and at the same time travels a horizontal distance <em>x. </em>

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance <em>y </em>using the equation,

y=u_yt+\frac{1}{2} gt^2

Substitute 0 m/s for u_y, 9.81 m/s²for <em>g</em> and 1.5 m for <em>y</em>.

y=u_yt+\frac{1}{2} gt^2\\ 1.5 m=(0m/s)t+\frac{1}{2} (9.81m/s^2)t^2\\ t=\sqrt{\frac{2(1.5m)}{9.81m/s^2} } =0.5530s

The horizontal distance traveled by the bullet is given by,

x=u_xt

Substitute 500 m/s for u_x and 0.5530s for t.

x=u_xt\\ =(500m/s)(0.5530s)\\ =276.5m

The bullet travels a distance of 276.5 m.


5 0
3 years ago
The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What
Romashka [77]

The formula we need to use is displacement.

d=\Delta{x}=x_f-x_i, where xf is final position and xi is initial position.

We report the final position of 5 and the displacement of 2 so the formula is now:

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So the initial position of truck A is 3.

Hope this helps.

r3t40

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A ball is thrown with an initial velocity of u=(10i +15j) m/s. Whan it reaches the top of it trajectory neglecting air resistanc
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Answer:

v = (10 i ^ + 0j ^) m / s,    a = (0i ^ - 9.8 j ^) m / s²

Explanation:

This is a missile throwing exercise.

On the x axis there is no acceleration so the velocity on the x axis is constant

           v₀ₓ =  10 m / s

On the y-axis velocity is affected by the acceleration of gravity, let's use the equation

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at the highest point of the trajectory the vertical speed must be zero

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Answer:

1 35°

2 20°

3 50°

..............

7 0
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