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3 years ago

If the potential difference across the bulb in a camping lantern is 9.0 V, what is the

Physics

1 answer:

Gre4nikov [31]3 years ago

4 0

Answer:

Explanation:

The potential difference across the terminal as the same and thats because we are assuming that the source has no internal resistance.

Internal resistance are usually little resistances in the supply.

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Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng

garik1379 [7]

An electromagnet is a type of magnet in which the magnetic field is produced using the current. The simplest form of an electromagnet is a wire wrapped around in a coil.
The strength of magnetic field of such magnet is given with this equation:
$B=\frac{NI\mu}{L}$
Where N is the number of loops in the coil, I is the strength of the current flowing through the coil, L is the length of the coil, and $\mu$ is permeability of the electromagnet core material.
From this equation, we can see that increasing both the current and number of loops will increase the strength of the magnet.
Both BLANKS should be Increase. When you use the additional battery you will have more voltage and more voltage means more electricity.

5 0

3 years ago

True or false elliptical galaxies are made up of old stars containing small amount of gas

ch4aika [34]

True, They contain old stars and posses little gas or dust

6 0

3 years ago

A bowling ball of mass 5 kg rolls down a slick ramp 20 meters long at a 30 degree angle to the horizontal. What is the work done

Elena-2011 [213]

Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

$W = F*d$

Where:

F: is the force

d: is the displacement = 20 m

The force is equal to the weight (W) in the x component:

$F = W_{x} = mgsin(\theta)$

Where:

m: is the mass of the bowling ball = 5 kg

g: is the gravity = 9.81 m/s²

θ: is the degree angle to the horizontal = 30°

$F = mgsin(\theta) = 5 kg*9.81 m/s^{2}*sin(30) = 24.53 N$

Now, we can find the work:

$W = F*d = 24.53 N*20 m = 490.6 J$

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

6 0

3 years ago

SOMEONE HELP ME PLSS

lara31 [8.8K]

1. 2500/60 joules/sec
2. 2,500Nm

7 0

3 years ago

Read 2 more answers

Which statements describe a fully charged capacitor? Check all that apply.

Oksanka [162]

Well, first of all, there's no such thing as "fully charged" for a capacitor.

A capacitor has a "maximum working voltage", because of mechanical
or chemical reasons, just like a car has a maximum safe speed. But
anywhere below that, cars and capacitors do their jobs just fine, without
any risk of failing.

So we have a capacitor that has some charge on it, and therefore some
voltage across it. From the list of choices above . . .

-- Both plates have the same amount of charge.
Yes. And both plates have opposite TYPES of charge.
One plate is loaded with electrons and is negatively charged.
The other plate is missing electrons and is positively charged.

-- There is a potential difference between the plates.
Yes. That's the "voltage" mentioned earlier.
It's a measure of how badly the extra electrons want to jump
from the negative plate to the positive plate.

-- Electric potential energy is stored.
Yes. It's the energy that had to be put into the capacitor
to move electrons away from one plate and cram them
onto the other plate.

4 0

3 years ago

Read 2 more answers