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tia_tia [17]
2 years ago
11

A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?

Physics
2 answers:
love history [14]2 years ago
6 0

Answer:

R\approx12.43 \,\, \Omega

Explanation:

We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:

V=I\,\,R\\R = \frac{V}{I} \\R=\frac{87}{7} \\R\approx12.43 \,\, \Omega

kramer2 years ago
3 0

Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

I would appreciate it!

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Detailed explanation and calculation is shown in the image below

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