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blsea [12.9K]
1 year ago
8

The density of ice is 920 kg/m³ and that of water is 1000 kg/m³ calculate the relative density​

Chemistry
1 answer:
STatiana [176]1 year ago
7 0

When the density of ice is 920 kg/m³ and that of water is 1000 kg/m³ then the relative density​ will be 0.92 kg/m³​

The ratio of a substance's density to given reference material is known as its relative density. For gases, the reference is air at room temperature, but relative gravity for liquids is almost often calculated in relation to the densest possible form of water.

RD= ρ substance/ρ reference

ρ substance = the density of the substance = 920 kg/m³

ρ water = the density of water at 4.0°C, 1000 kg/m3

RD = 920/1000 kg/m³

RD= 0.92kg/m³

Learn more about density here:

brainly.com/question/15164682

#SPJ9

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How many gallons in 2 L bottle
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Give examples to three solutions you commonly use and identify the solvent and solutes that make it each up.
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Mouthwash:
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hope this helps!!

8 0
3 years ago
Read 2 more answers
If all the water in 430.0 mL of a 0.45 M NaCI solution evaporates what is the mass of NaCI will remain
skad [1K]

Answer:

11.31 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).</em>

<em></em>

<em>∴ mass of NaCl remained after evaporation of water = (M)(V of the solution (L))(molar mass)</em> = (0.45 M)(0.43 L)(58.44 g/mol) = <em>11.31 g.</em>

6 0
3 years ago
Read 2 more answers
A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

M_2 = 32 \times ( 1.273092369)^2

M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

7 0
3 years ago
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