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1 year ago

The density of ice is 920 kg/m³ and that of water is 1000 kg/m³ calculate the relative density

1 answer:

7 0

When the density of ice is 920 kg/m³ and that of water is 1000 kg/m³ then the relative density will be 0.92 kg/m³

The ratio of a substance's density to given reference material is known as its relative density. For gases, the reference is air at room temperature, but relative gravity for liquids is almost often calculated in relation to the densest possible form of water.

RD= ρ substance/ρ reference

ρ substance = the density of the substance = 920 kg/m³

ρ water = the density of water at 4.0°C, 1000 kg/m3

RD = 920/1000 kg/m³

RD= 0.92kg/m³

Learn more about density here:

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What's is the mass of 0.500 mol NH3

Setler [38]

Answer:

8.5155g NH3

Explanation:

the molar mass of NH3 is 17.031 g/mol

0.5 mol NH3 x 17.031 gNH3/1 mol NH3 = 8.5155g NH3

4 0

3 years ago

Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu

Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

$r = \dfrac{a}{2\sqrt{2}}$

where;

a = edge length.

Making "a" the subject of the formula:

$a = 2 \sqrt{2} \times r$

$a = 2 \times 1.414 \times 135 \ pm$

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

$density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}$

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

$mass\ of\ atom =\dfrac{ atomic \ mass}{Avogadro \ number}$

$mass\ of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}$

Recall also that number of atoms in a unit cell for a face-centered cubic = 4

So;

$mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4$

mass of unit cell = 6.83380375 × 10⁻²² g

$Density \ of \ unit \ cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}$

Density of unit cell ( rhodium) = 12.279 g/cm³

3 0

2 years ago

Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of

jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x

Total energy required = $2260x+x\times2.010\times(135-100)=2260x+70.35x=2330.35x$

$2330.35x=1048815\\x=450.068g$

Hence, there was 450.068g of water in the pot.

8 0

2 years ago

200cm3 of oxygen diffuse through a porous partition in 10 seconds. How long will it take 120cm3 of chlorine to diffuse through t

Lubov Fominskaja [6]

If 200cm^3 takes 10secs then 120 will take 6secs. i hope u understood

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3 years ago

Defined as the negative logarithm of the concentration of OH-

Marat540 [252]

Answer:

As with the hydrogen-ion concentration, the concentration of the hydroxide ion can be expressed logarithmically by the pOH. The pOH of a solution is the negative logarithm of the hydroxide-ion concentration. pOH=−log[OH−] The pH of a solution can be related to the pOH.

4 0

3 years ago

The density of ice is 920 kg/m³ and that of water is 1000 kg/m³ calculate the relative density​

The density of ice is 920 kg/m³ and that of water is 1000 kg/m³ calculate the relative density