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blsea [12.9K]
1 year ago
8

The density of ice is 920 kg/m³ and that of water is 1000 kg/m³ calculate the relative density​

Chemistry
1 answer:
STatiana [176]1 year ago
7 0

When the density of ice is 920 kg/m³ and that of water is 1000 kg/m³ then the relative density​ will be 0.92 kg/m³​

The ratio of a substance's density to given reference material is known as its relative density. For gases, the reference is air at room temperature, but relative gravity for liquids is almost often calculated in relation to the densest possible form of water.

RD= ρ substance/ρ reference

ρ substance = the density of the substance = 920 kg/m³

ρ water = the density of water at 4.0°C, 1000 kg/m3

RD = 920/1000 kg/m³

RD= 0.92kg/m³

Learn more about density here:

brainly.com/question/15164682

#SPJ9

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Because this is Avogadro constant<span> (the number of </span>constituent particles, in this example atoms of gold<span> that are contained in the </span>amount of substance<span> given by one </span>mole). <span>The </span>mole<span> is the </span>unit of measurement<span> for </span>amount of substance, t<span>he mole is an </span>SI base unit<span>, with the unit symbol </span>mol<span>.</span>

6 0
3 years ago
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What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?
ArbitrLikvidat [17]
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


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3 years ago
Help help help ! *10 points*
Aleonysh [2.5K]
Search web will get a superb answers for it than individuals opinion
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Here it is how to solve.
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