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There are five constitutional isomers with the molecular formula C6H14. When treated with chlorine at 300°C, isomer A gives a mi

ozzi

Answer:

Pentane or 2,2-dimethylbutane

Explanation:

I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.

The results are

Isomer 1— three sets of equivalent hydrogens

Isomer 2— five sets of equivalent hydrogens

Isomer 3— four sets of equivalent hydrogens

Isomer 4— two sets of equivalent hydrogens

Isomer 5— three sets of equivalent hydrogens

Each set will give one monochloro substitution product.

4 = A. Two monochloro isomers.

2 = B. Five monochloro isomers.

3 = C. Four monochloro isomers.

Isomers 1 and 5 each give three monochloro isomers.

Thus, we cannot assign Structure D definitively.

D is either pentane or 2,2-dimethylbutane.

5 0

3 years ago

Hello! I need a bit of help and Im kinda in a bit of a hurry so please help! Thank you :D

Scorpion4ik [409]

The first one is substance 3
The second one is Oxygen, Helium, and carbon dioxide
The third one is the oil floats on top of the water

8 0

3 years ago

Read 2 more answers

The question is in the attached word document.

Alekssandra [29.7K]

Answer:i read it Explanation:

3 0

2 years ago

A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH₄NO₃ and 4.42 g of (NH₄)₃ PO₄ in enoug

Alexandra [31]

In finding the molarity of a solution, we use the following formula:

$M=moles soluteL solution$

What is Molarity?

The number of moles of the solute is calculated by dividing the mass of the solute by its molar mass.

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The molar mass of NH4NO3 and (NH4)3PO4 are 80.043 g/mol and 149.0867 g/mol, respectively.

$molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol$

$molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol$

$total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol$

$molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol$

$[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4$

$[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4$

Therefore, $[PO3−4]\\$ has a molarity of $1.48×10−3 M PO3−$

To learn more about Molarity click on the link below:

brainly.com/question/19943363

#SPJ4

5 0

2 years ago

Select the correct value for the indicated bond angle in each of the following compounds: O-S-O angle of SO2 F-B-F angle of BF3

Stels [109]

Answer:

(A) O-S-O bond angle of SO₂ molecule = 119°

(B) F-B-F bond angle of BF₃ molecule = 120°

(C) Cl-S-Cl bond angle of SCl₂ molecule = 103°

(D) O-C-O bond angle of CO₂ molecule = 180°

(E) F-P-F bond angle of PF₃ molecule = 96.3°

(F) H-C-H bond angle of CH₄ molecule = 109.5°

Explanation:

Bond angle refers to the angle between two adjacent chemical bonds in a molecule. The bond angle is different for different molecular geometry.

The Valence shell electron pair repulsion theory predicts the molecular geometry and shape of the given molecule by the number of lone pairs on central atom and number of atoms bonded to central atom.

(A) SO₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 1

Therefore, the shape of SO₂ molecule is bent and the O-S-O bond angle is 119°.

(B) BF₃ molecule

The number of atoms bonded to B = 3

Number of lone pairs on B = 0

Therefore, the shape of BF₃ molecule is trigonal planar and the F-B-F bond angle is 120°.

(C) SCl₂ molecule

The number of atoms bonded to S = 2

Number of lone pairs on S = 2

Therefore, the shape of SCl₂ molecule is bent and the Cl-S-Cl bond angle is 103°.

(D) CO₂ molecule

The number of atoms bonded to C = 2

Number of lone pairs on C = 0

Therefore, the shape of CO₂ molecule is linear and the O-C-O bond angle is 180°.

(E) PF₃ molecule

The number of atoms bonded to P = 3

Number of lone pairs on P = 1

Therefore, the shape of PF₃ molecule is trigonal pyramidal and the F-P-F bond angle is 96.3°.

(F) CH₄ molecule

The number of atoms bonded to C = 4

Number of lone pairs on C = 0

Therefore, the shape of CH₄ molecule is tetrahedral and the H-C-H bond angle is 109.5°.

7 0

3 years ago