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cupoosta [38]
3 years ago
14

Which of the following why use approximately represent the number of atoms in one mole of gold

Chemistry
2 answers:
natka813 [3]3 years ago
6 0
Answer is: D. 6.02 x 1023. 
Because this is Avogadro constant<span> (the number of </span>constituent particles, in this example atoms of gold<span> that are contained in the </span>amount of substance<span> given by one </span>mole). <span>The </span>mole<span> is the </span>unit of measurement<span> for </span>amount of substance, t<span>he mole is an </span>SI base unit<span>, with the unit symbol </span>mol<span>.</span>

Kazeer [188]3 years ago
4 0

Answer: The answer is D. 6.02 x 10^23

Explanation: I took the quiz

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scZoUnD [109]
Covalent bonds but not ionic 
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Calculate the density of a cube of iron that measures 3.50cm, 0.755 cm, 2.25cm on each side and weighs 47.0g?
laila [671]

Answer: 7.90 g/cm^3

Explanation:

Density = Mass / Volume

The first step is to find the volume by multiplying the three measures of the cube that have been provided.

3.50 x 0.755 x 2.25 = 5.95 cm^3

Now we can plug the numbers into our equation.

Density = 47.0g / 5.95 cm^3

Density = 7.90 g/cm^3

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3 years ago
What volume of 0.205 m k3po4 solution is necessary to completely react with 154 ml of 0.0110 m nicl2? 1.65 l?
sasho [114]
The balanced equation for the above reaction is 
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stoichiometry of K₃PO₄  to NiCl₂ is 2:3
the number of NiCl₂ moles reacted - 0.0110 mol/L x 0.154 L = 1.69 x 10⁻³ mol
if 3 mol of NiCl₂ reacts with - 2 mol of K₃PO₄ 
then 1.69 x 10⁻³ mol of NiCl₂ reacts with - 2/3 x 1.69 x 10⁻³  = 1.13 x 10⁻³ mol of K₃PO₄
molarity of K₃PO₄ solution given - 0.205 M
there are 0.205 mol in 1 L
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3 years ago
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Answer:

Option D. pH= 1.3 strong acid

Explanation:

From the question given:

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8 0
3 years ago
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