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2 years ago

Which regions of the world seem to be suffering most from loss of species ?

Chemistry

1 answer:

Lana71 [14]2 years ago

3 0

Answer:

The most dangerous area for animals and plants is the one that contains the greatest biodiversity on the planet: Southeast Asia. In this region are the five most affected countries in the world: Malaysia, Brunei, Singapore, Indonesia and Thailand. The Atlantic rainforests of Brazil are also very affected, this is due to the fact that great catastrophes have occurred in these places lately, such as the massive fire in the Amazon, and the floods that occurred after the tremendous absence of vegetation that these places suffered.

Explanation:

Also on the other hand, the regions with the highest extinction are those that carry out little environmental policies where care has not been taken for species that are in danger of extinction, as happens, for example, in those islands such as the Galapagos Islands, which are subject to severe fines for harm turtles.

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saul85 [17]

Answer:

I think it's just density of the tuna

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3 years ago

What do you look at to tell the reactivity of an atom?

tia_tia [17]

Answer:

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Explanation:

I hope this helped!

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3 years ago

What does cpd in organic chemistry mean?

makvit [3.9K]

It means a substance formed by chemical union of 2 or more elements or ingredients in definite proportion by weight.

4 0

3 years ago

The freezing point of benzene is 5.5°C. What is the freezing point of a solution of 2.60 g of naphthalene (C10H8) in 675 g of be

Mrac [35]

Answer: The freezing point of solution is 5.35°C

Explanation:

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 4.90°C/m

$m_{solute}$ = Given mass of solute (naphthalene) = 2.60 g

$M_{solute}$ = Molar mass of solute (naphthalene) = 128.2 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 675 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 4.90^oC/m\times \frac{2.60\times 1000}{128.2g/mol\times 675}\\\\\text{Freezing point of solution}=5.35^oC$

Hence, the freezing point of solution is 5.35°C

3 0

2 years ago

AL2(SO4)2.XH2O has 8.1% aluminium by mass.The value of X ?

In-s [12.5K]

Answer:

jgutxutututrxxtdr

Explanation:

cjycitxutxtucj

5 0

2 years ago