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frozen [14]
2 years ago
14

Which regions of the world seem to be suffering most from loss of species ?

Chemistry
1 answer:
Lana71 [14]2 years ago
3 0

Answer:

The most dangerous area for animals and plants is the one that contains the greatest biodiversity on the planet: Southeast Asia. In this region are the five most affected countries in the world: Malaysia, Brunei, Singapore, Indonesia and Thailand. The Atlantic rainforests of Brazil are also very affected, this is due to the fact that great catastrophes have occurred in these places lately, such as the massive fire in the Amazon, and the floods that occurred after the tremendous absence of vegetation that these places suffered.

Explanation:

Also on the other hand, the regions with the highest extinction are those that carry out little environmental policies where care has not been taken for species that are in danger of extinction, as happens, for example, in those islands such as the Galapagos Islands, which are subject to severe fines for harm turtles.

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The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
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<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

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